Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
Answer:Solve. 2a + 3b = 5 6= a -5 a = 4 b = -1 1 a = 6 b=1 a=6 6 = -1 a=4 6 = 1
Step-by-step explanation:
Answer:
x = 19
Step-by-step explanation:
Since DF is an angle bisector then it divides the opposite sides into segments that are proportional to the other 2 sides, that is
= 
, substitute values
= 
( cross- multiply )
22.5(x - 9) = 225 ( divide both sides by 22.5 )
x - 9 = 10 ( add 9 to both sides )
x = 19
Answer:
See below
Step-by-step explanation:
Your question is a bit unclear, so I'm going to assume you want the value of y or x:
(y+3)^2=-12(x-2)
-(y+3)^2/12=x-2
-(y+3)^2/12+2=x
(y+3)^2=-12(x-2)
y+3=sqrt(-12x+24)
y=sqrt(-12x+24)-3
