I NEED ANSWER ASAP WILL GIVE BRAINLIEST(WORTH 30 POINTS)

erica [24]

Answer:

15

Step-by-step explanation:

Simply subtract the smaller number from the bigger number, and divide by 2. Or add the two numbers together and divide by 2.

6 0

3 years ago

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The yearly cost in dollars , y, at a video game arcade based on total game tokens purchased, x, is y = 1/10x + 60 for a member a

Bond [772]

The graph of a non member's yearly cost is steeper, and also has a lower y-intercept. And the graph of a member's yearly cost starts higher, but is less steep.

5 0

3 years ago

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<img src="https://tex.z-dn.net/?f=f%28x%29%3D%281-0.08%29%5E%7B%5Cfrac%7B1%7D%7B12%7D%20%7D%20%5E%7B%2812t%29%7D" id="TexFormula

oksano4ka [1.4K]

Answer:

See Below.

Step-by-step explanation:

We have:

$\displaystyle f(x)=(1-0.08)^{\frac{1}{12}(12t)}$

First, we can subtract within the parentheses:

$f(x)=(0.92)^{\frac{1}{12}(12t)}$

By the properties of exponents:

$f(x)=((0.92)^\frac{1}{12})^{12t}$

Approximate. Use a calculator:

$f(x)\approx (0.993)^{12t}$

Notes:

0.993 is only an approximation, hence the approximately equal sign.

I'm not given the context of the problem, but it's simpler to just simplify in the exponent like so (the fractions cancel):

$\displaystyle f(x)=(1-0.08)^{\frac{1}{12}(12t)}=(0.92)^t$

Full Problem:

The value of Sara's car decreases at a rate of 8% per year.

We will use the exponential decay formula with a set time, given by:

$f(x)=a(r)^{x/d}$

Where a is the initial value, r is the rate, x is the time that has passed (dependent on d), and d is the amount of time for one decrease.

For this problem, we can ignore the initial value.

And since the value decreases at a rate of 8% per year, r = 0.92 (we acquire this from 1 - 0.08).

Part 1) Per Month:

Since it decreases per month, d = 12.

$f(x)=(0.92)^{x/12}$

Approximate:

$f(x)=((0.92)^{1/12})^x\approx(.993)^x$

In this case, x is measured in months.

Part 2) Per Week:

Since it decreases per week, d = 52.

$f(x)=(0.92)^{x/52}$

Approximate:

$f(x)=((0.92)^1/52)^x\approx (.998)^x$

In this case, x is measured in weeks.

Part 3) Per Day:

So, d = 365.

$f(x)=(0.92)^{x/365}$

Simplify:

$f(x)=((0.92)^{1/365})^x\approx(.999)^x$

In this case, x is measured in days.

Part 4)

So, as d increases, our r increases as well.

Therefore, the smaller the time interval (from months to weeks to days), the higher our rate of decrease is.

8 0

3 years ago

What is the distance between (-3,1) and (-2,-1) in units

Nastasia [14]

Answer:

Here is the graph I made, starting from (-3,1) to (-2,-1) it goes down 2 units and over 1 unit.

6 0

3 years ago

The second term in a geometric sequence is 12. The fourth term in the same sequence is 4/3. What is the common ratio in this seq

aniked [119]

The common ratio in this sequence is 6:2 or 4:3

3 0

3 years ago

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