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Thepotemich [5.8K]
2 years ago
7

c) If you are given a circle with center C, how do you locate the vertices of a square inscribed in circle C?

Mathematics
1 answer:
Advocard [28]2 years ago
5 0

Answer: The square is inscribed in a circle that means the square is drawn inside a circle such that it's vertices lie on the circle.

You need to remember that the vertices of the square lie on the circumference of circle and the center of circle is also the midpoint of diagonals of the square i.e. Diagonal of the square is equal to diameter of the circle.

We could also see the image of such figure.

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29 less than -10 times a number is equal to -18 times a number +91
sergejj [24]

Answer:

10

Step-by-step explanation:

5 0
4 years ago
Simplify the given equation.
77julia77 [94]

Answer:

2) 7x-6=2x+2

Step-by-step explanation:

It equals 8/9, and the equation, (5x + 2(x-3) = -2(x - 1)) equals 8/9 as well.

7 0
2 years ago
Read 2 more answers
A random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6. A random sample of 17 su
Sladkaya [172]

Answer:

We conclude that there is no difference in potential mean sales per market in Region 1 and 2.

Step-by-step explanation:

We are given that a random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6.

A random sample of 17 supermarkets from Region 2 had a mean sales of 78.3 with a standard deviation of 8.5.

Let \mu_1 = mean sales per market in Region 1.

\mu_2  = mean sales per market in Region 2.

So, Null Hypothesis, H_0 : \mu_1-\mu_2 = 0      {means that there is no difference in potential mean sales per market in Region 1 and 2}

Alternate Hypothesis, H_A : > \mu_1-\mu_2\neq 0      {means that there is a difference in potential mean sales per market in Region 1 and 2}

The test statistics that will be used here is <u>Two-sample t-test statistics</u> because we don't know about population standard deviations;

                            T.S.  =  \frac{(\bar X_1 -\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+ {\frac{1}{n_2}}} }   ~  t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean sales in Region 1 = 84

\bar X_2 = sample mean sales in Region 2 = 78.3

s_1  = sample standard deviation of sales in Region 1 = 6.6

s_2  = sample standard deviation of sales in Region 2 = 8.5

n_1 = sample of supermarkets from Region 1 = 12

n_2 = sample of supermarkets from Region 2 = 17

Also, s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times  s_2^{2}  }{n_1+n_2-2} }  = s_p=\sqrt{\frac{(12-1)\times 6.6^{2}+(17-1)\times  8.5^{2}  }{12+17-2} } = 7.782

So, <u><em>the test statistics</em></u> =  \frac{(84-78.3)-(0)}{7.782 \times \sqrt{\frac{1}{12}+ {\frac{1}{17}}} }  ~   t_2_7

                                   =  1.943  

The value of t-test statistics is 1.943.

 

Now, at a 0.02 level of significance, the t table  gives a critical value of -2.472 and 2.473 at 27 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have<u><em> insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that there is no difference in potential mean sales per market in Region 1 and 2.

6 0
3 years ago
Simplify.<br> 10u -4u<br> Please help
vovikov84 [41]

Answer:

6u

Step-by-step explanation:

The two terms 10u and 4u are like terms because they both carry the same variable (u) with the same degree (1). So, we can just subtract them as if they were normal numbers 10 - 4:

10u - 4u = 6u

Thus, the answer is 6u.

Hope this helps!

8 0
3 years ago
Read 2 more answers
Mr. Janson paid for admission to the high school football game for his family. He purchased 3 adult tickets and 2 student ticket
Vilka [71]

Answer: adult ticket : 5.50

Student ticket : 2.75

Step-by-step explanation:

8 0
3 years ago
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