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I am Lyosha [343]
3 years ago
15

4. Which of the following points are solutions to the system of inequalities 2x - 3y > 9 and -x -

Mathematics
1 answer:
Helen [10]3 years ago
7 0

Answer:

(1, -3)

Step-by-step explanation:

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An adult sleeps about 480 per day. In infant sleeps about 820 minutes per day. About how many more minutes does an infant sleep
AysviL [449]
(820*7)-(480*7)=? This is how to solve the equation

6 0
3 years ago
Which inequality matches the graph?
Papessa [141]

Given:

The dotted boundary line passes through the points (-3,-8), (1,-2) and (9,10).

Above line is shaded.

To find:

The inequality for the given graph.

Solution:

Consider any two points on the line. Let the two points are (1,-2) and (9,10). So, the equation of the line is:

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-(-2)=\dfrac{10-(-2)}{9-1}(x-1)

y+2=\dfrac{10+2}{8}(x-1)

y+2=\dfrac{12}{8}(x-1)

y+2=\dfrac{3}{2}(x-1)

Multiply both sides by 2.

2(y+2)=3(x-1)

2y+4=3x-3

2y-3x=-3-4

-3x+2y=-7

Above line is shaded and the boundary line is a dotted line. So, the sign of inequality must be >.

-3x+2y>-7

This inequality is not in the equations. So, multiply both sides by -1 and change the inequality sign.

(-3x+2y)(-1)

3x-2y

Therefore, the correct option is D.

8 0
3 years ago
Please help me with 5 or 6 anyone you like thank you so much
Greeley [361]
The answer would b C
6 0
3 years ago
Read 2 more answers
Find the values of c such that the area of the region bounded by the parabolas y = 4x2 − c2 and y = c2 − 4x2 is 32/3. (Enter you
Misha Larkins [42]

Answer:

-2,2

Step-by-step explanation:

Let

y_1=4x^2-c^2

y_2=c^2-4x^2

We have to find the value of c such that the are of the region bounded by the parabolas =32/3

y_1=y_2

4x^2-c^2=c^2-4x^2

4x^2+4x^2=c^2+c^2

8x^2=2c^2

x^2=c^2/4

x=\pm \frac{c}{2}

Now, the area bounded by two curves

A=\int_{a}^{b}(y_2-y_1)dx

A=\int_{-c/2}^{c/2}(c^2-4x^2-4x^2+c^2)dx

\frac{32}{3}=\int_{-c/2}^{c/2}(2c^2-8x^2)dx

\frac{32}{3}=2\int_{-c/2}^{c/2}(c^2-4x^2)dx

\frac{32}{3}=2[c^2x-\frac{4}{3}x^3]^{c/2}_{-c/2}

\frac{32}{3}=2(c^2(c/2+c/2)-4/3(c^3/8+c^3/28))

\frac{32}{3}=2(c^3-\frac{4}{3}(\frac{c^3}{4}))

\frac{32}{3}=2(c^3-\frac{c^3}{3})

\frac{32}{3}=2(\frac{2}{3}c^3)

c^3=\frac{32\times 3}{4\times 3}

c^3=8

c=\sqrt[3]{8}=2

When c=2 and when c=-2 then the given parabolas gives the same answer.

Therefore, value of c=-2, 2

7 0
3 years ago
8/9 -1/3 i don't know
Brilliant_brown [7]

5/9

brainliest please x

4 0
3 years ago
Read 2 more answers
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