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3 years ago

After the 30% discount was applied, Patricia paid $45.50 for the ring. What was the original price of the ring

Mathematics

1 answer:

romanna [79]3 years ago

3 0

45.50*.30 = 13.65
13.65+45.50 = 59.15

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If cos 0=2/3, what are the values of sin 0 and tan 0?

morpeh [17]

Answer:

Below

Step-by-step explanation:

● cos O = 2/3

We khow that:

● cos^2(O) + sin^2(O) =1

So : sin^2 (O)= 1-cos^2(O)

● sin^2(O) = 1 -(2/3)^2 = 1-4/9 = 9/9-4/9 = 5/9

● sin O = √(5)/3 or sin O = -√(5)/3

So we deduce that tan O will have two values since we don't khow the size of O.

■■■■■■■■■■■■■■■■■■■■■■■■■

●Tan (O) = sin(O)/cos(O)

● tan (O) = (√(5)/3)÷(2/3) or tan(O) = (-√(5)/3)÷(2/3)

● tan (O) = √(5)/2 or tan(O) = -√(5)/2

4 0

3 years ago

Help please i give brainliast)

masha68 [24]

x|y............................

5|10

6|20

6|23

7|35

7 0

3 years ago

Read 2 more answers

HELP PLEASE WILL MARK BRAINLIEST!!

Arte-miy333 [17]

Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

$from \: the \: figure \\ AB = 300 \: ft \: \: \: angle \: C = 60 \:( theta)\: degress \\ in \: triangle \: ABC \: using \: tan \: theta\\ \tan(60) = \frac{opposite \: side}{adjacent \: side} \\ \tan(60) = \frac{300}{BC} \\ \sqrt{3} = \frac{300}{BC} \\ BC = \frac{300}{ \sqrt{3} } \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\ \tan(30 ) =\frac{opposite \: side}{adjacent \: side} \\ \tan(30) = \frac{300}{BD} \\ \frac{1}{ \sqrt{ 3} } = \frac{300}{BD} \\ BD = 300 \sqrt{3} \\ CD = BD - BC \\ = 300 \sqrt{3 } - 100 \sqrt{3} \\ = (300 - 100) \sqrt{3} \\ = 200 \sqrt{3 } \\ = 200 \times 1.732 \\ = 346.4 \: ft$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

7 0

3 years ago

What is 1 1/3 times 1 4/9 in fraction form

nikitadnepr [17]

Answer:

52 / 27

Step-by-step explanation:

3 0

2 years ago

How to solve it with walk through steps

mario62 [17]

You can say

x+y=5
x=5-y

You know the value of x, put it into the next equation.

3(5-y)-7y=19
15-3y-7y=19
15-19 = 10y
-4=10y
-4/10=y
-2/5=y

Put y value back into either equation to find value of x.

x+y=5
x-2/5=5
x=5+2/5
x=27/5

Therefore, x,y = (27/5, -2/5)

Hope I helped :)

6 0

3 years ago