Answer:
547 m
Step-by-step explanation:
Given :
Angle of depression, θ = 63°43' ; 43/60 = 0.7167 = 63 + 0.7167 = 63.7167°
The height, h = 270
The distance of park bench from the building, d is given by :
Tan θ = opposite / Adjacent
Tan 63.7167 = d / 270
d = 270 * Tan 63.7167
d = 546.70459
d, distance of Park bench from building is 547 m
Answer:
2
Step-by-step explanation:
2^2+4(2)=12
4+8=12
So, x=2
Hope this helps.
-Amelia
6/8. multiply 3/4 by 2 and there is your answer.
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
Answer:
...
Step-by-step explanation:
14, 18, 20
