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Brums [2.3K]
2 years ago
7

A quadrilateral can be inscribed in a circle, if and only if, the opposite angles in that quadrilateral are supplementary.

Mathematics
1 answer:
balandron [24]2 years ago
4 0

The cyclic quadrilateral's opposing angles are 180 degrees, which become supplementary angles.

<h3>What is a cyclic quadrilateral?</h3>

If the quadrilateral is inscribed in a circle then the quadrilateral is known as a cyclic quadrilateral.

A quadrilateral can be inscribed in a circle, if and only if, the opposite angles in that quadrilateral are supplementary.

We know that the sum of the opposite angles of the cyclic quadrilateral is equal to 180 degrees.

Supplementary angle - Two angles are said to be supplementary angles if their sum is 180 degrees.

More about the cyclic quadrilateral link is given below.

brainly.com/question/15061291

#SPJ1

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Function f is shown on the graph
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Answer:

Option A, (-4, -1)

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6 0
3 years ago
How kany doulutions does this equation have 25 - 4x=15-3x+10-x
natima [27]
Since it's a one-variable equation, it has only one solution:

25 - 4x = 15 - 3x + 10 - x

25 - 4x + x = 15 - 3x + 10

25 - 3x = 15 - 3x + 10

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0 = 15 - 15

0 = 0




Hope it helped,



BioTeacher101
4 0
4 years ago
A circular quilt is made from 113.04 square feet of fabric. How much trim is needed to go around it’s edge?
erik [133]

Hey there!

We are looking for the circumference of the circle, which is the distance around it. We are given the area, which is the radius squared times pi.

First, we need to undo the area to find our radius.

113.04/3.14=36

We square root this to find the radius.

√36=6

Our radius is six. To find the circumference, we need to multiply the diameter by pi. The diameter is twice the radius.

6*2=12

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6 0
3 years ago
A: What are the solutions to the quadratic equation x^2+9=0?
Nataliya [291]

Answer:

Part A)

x=-3i

x=3i

Part B)

(x+3i)(x-3i)

Step-by-step explanation:

Given:

Part A)

x^2+9=0

x^2=-9

x= √-9

x=√-1 *√9

x=± i *3

x=±3i

Part B)

x^2+9=0

x^2 - (-9)=0

x2-(3i)^2=0

(x-3i)(x+3i)=0 !

3 0
3 years ago
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Juli2301 [7.4K]
First we define the varible to use:
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5 0
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