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geniusboy [140]
3 years ago
5

A person is standing 24 feet away from a street light that is 25 feet tall. How tall is he if his shadow is 6 feet long?

Mathematics
1 answer:
SVEN [57.7K]3 years ago
3 0

Answer:

Step-by-step explanation:

The triangle formed by the lamp post and the (24+6)foot side on the ground is similar to the right triangle formed by the person of height h and his 6 foot shadow.

H/25=6/36

H=5

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Which collection of three side lengths will not form a triangle
dezoksy [38]

Answer:

Any collection of lengths (a, b, c) which do not satisfy the triangle inequalities.

Step-by-step explanation:

Any collection (a, b, c) which do not satisfy the triangle inequalities. The inequalities:

a + b > c

b + c > a

a + c > b

You will need to test all of your options on the three inequalities above. If any one of the three fails, the collection won't work.

4 0
3 years ago
Your teacher announced a 50-point math quiz for tomorrow. The quiz will have 15 questions with word problems worth 4 points each
koban [17]

Answer:

5  word problems(4points each)      &      10 open (3 points each)

Step-by-step explanation:

O= open response

W= word problems

  W+O =15

4W + 3O = 50

multiply the first by -3 to eliminate O

-3W -3O = -45

4W  + 3O = 50

  AD BOTH

W = 5    ( 5 questions word problems)

O= 10   ( 10 questions open response)

  5x4 = 20

10x3 = 30

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3 0
2 years ago
What is 4x-7xy+9xy-7pq
konstantin123 [22]
Answer:  " 4x + 2xy - 7pq " .
___________________________________
Explanation:
___________________________________
Given:  
" <span>4x - 7xy + 9xy - 7pq " ;  Simplify the expression;
___________________________________
  Combine the "like terms:
___________________________________
       -7xy + 9xy = 2xy ;
___________________________________
Now, rerewrite the expression, substituting the "-7xy + 9xy";  with " + 2xy" ;
___________________________________
   </span>→ " 4x + 2xy - 7pq " .
<span>___________________________________


</span>
4 0
3 years ago
What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?
xxMikexx [17]

We have been given an equation of hyperbola \frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1. We are asked to find the center of hyperbola.  

We know that standard equation of a vertical hyperbola is in form \frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1, where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1

Now we can see that value of k is -3. Therefore, the vertex of given hyperbola will be at point (6,-3) and option D is the correct choice.

6 0
3 years ago
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PSYCHO15rus [73]
Y=X2+28 PEMDAS says first do parentheses
exponent
multiply
divide
add
subtract
3 0
3 years ago
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