In order to answer this, we mus know the data for the heat of combustion of propane. This is an empirical data that you can search online. The heat of combustion is -2220 kJ/mol. The molar mass of propane of 44.1 g/mol. The solution is as follows:
ΔH = -2220 kJ/mol (1 mol/44.1 g)(1000g/1kg)(20 kg)
<em>ΔH = -1006802.721 kJ or -1 GJ</em>
Answer:
2.02 g H₂
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Explanation:
<u>Step 1: Define</u>
22.4 L H₂ at STP
<u>Step 2: Identify Conversions</u>
STP - 22.4 L / mol
Molar Mass of H - 1.01 g/mol
Molar Mass of H₂ - 2(1.01) = 2.02 g/mol
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<u>Step 3: Convert</u>
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= 2.02 g H₂
Answer: C, 36,450.06 moles
Explanation:
Molar mass=478.41
17.19gx478.41moles=36,450.06
Answer:
When calcium carbonate reacts with hydrogen chloride, it reacts to form calcium chloride, carbon dioxide, and water. If this reaction occurs with 51.6% yield, what mass of carbon dioxide will be collected if 16.93 g of CaCO3 is added to sufficient hydrogen chloride
The total mass of magnesium chloride is 95.21g/mol
The mass of chlorine is 35.45g/mol
To find the mass percent of chlorine, divide its molar mass by the total mass of the substance and multiply the result by 100:
(35.45/95.21)(100)= 37.2%
