Answer:
D.
Explanation:
Meets the qualifications!
Answer:
D. 3.04 × 10^-19 J
Explanation:
c = lambda * nunu = c/lambda
E = h* nu
E = h * c/lambda = 6.626x10^-34 J-sec * 3x10^8 m/sec / 6.54x10^-7 m
E = 3.04x10^-19 J
Answer:
$25,985.25
Explanation:
Assuming it is compounded annually.
Answer:
3.00x107 cm
Explanation:
They answer would be the 4th one
Answer:
IODINE
Explanation:
The sublevel notation of the element:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵
To find this element, we must add the powers of the each of the sublevels. This is the number of electrons in the orbital of the atom.
2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 2 + 10 + 5 = 53
This give atom has 53 electrons and we can assume it to have an atomic number of 53.
The element is IODINE
