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Ray Of Light [21]

3 years ago

9

Before a bond breaks in a chemical reaction, what happens

1 answer:

Assoli18 [71]3 years ago

8 0

They have to form a chemical bond in order to brake them down first

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What those this best represent Dalton’s law Charles law

lubasha [3.4K]

Ideal Gas Law

Charles Law is a given volume mass of gas varies directly with the kelvin temperatures when the volume remains constant.

Daltons' Laws is, that at constant temperature, and pressure, the pressure of a mixture of gases that doesn't interact will be the sum of pressures of individual gases.

Hope that helps!!!

7 0

3 years ago

Complete the reaction

GarryVolchara [31]

1) (C2H5)2CBrCH2CH3 is the answer

explaiation:-

so when HBr is added to an alkene , according to the Markonicoff's rule ...H atoms are bonded to the C containing the most amount of H and Br is added to the other C.

2) Just add alkoholic KOH∆

6 0

3 years ago

7. Although carbon's three isotopes are carbon-12, carbon-13, and carbon-14, its

Naddik [55]

Answer:

B

Explanation:

carbon 12 is most useful to humans

4 0

2 years ago

The Density of pure carbon in Diamond form is 3.52 g/cm^3. How many cubic inches would 23.7 moles of pure diamond occupy?

Vedmedyk [2.9K]

Answer : The volume of pure diamond is $0.493inch^3$

Explanation : Given,

Density of pure carbon in diamond = $3.52g/cm^3$

Moles of pure diamond = 23.7 moles

Molar mass of carbon = 12 g/mol

First we have to calculate the mass of carbon or pure diamond.

$\text{ Mass of carbon}=\text{ Moles of carbon}\times \text{ Molar mass of carbon}$

Molar mass of carbon = 12 g/mol

$\text{ Mass of carbon}=(23.7moles)\times (12g/mole)=284.4g$

Now we have to calculate the volume of carbon or pure diamond.

Formula used:

$Density=\frac{Mass}{Volume}$

Now putting all the given values in this formula, we get:

$3.52g/cm^3=\frac{284.4g}{Volume}$

Volume = $80.8cm^3$

As we know that:

$1cm^3=0.061inch^3$

So,

Volume = $0.061\times 80.8inch^3$

Volume = $0.493inch^3$

Therefore, the volume of pure diamond is $0.493inch^3$

5 0

3 years ago

the hemiacetal below is treated with 18o-labeled methanol (ch3o*h) and acid. where will the label appear in the products?

ioda

The 18o-labeled methanol (CH3O*H) will appear in the products side at position b.

<h3>Position of 18o-labeled methanol in the products</h3>

The 18O label will appear at position b in the product as indicated in the image.

This methoxy group in the product formed in position b comes from the 18O-labeled methanol (CH3OH).

While the oxygens at positions a and c in the product come from the unlabeled hemiacetal.

Thus, the 18o-labeled methanol (CH3O*H) will appear in the products side at position b.

Learn more about methanol here: brainly.com/question/17048792
#SPJ11

8 0

1 year ago