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kvv77 [185]
3 years ago
11

Which of the following elements form cations (positively charged ions) readily? C, O, Na, Fe, As, Br, K

Chemistry
2 answers:
pentagon [3]3 years ago
8 0

e. Na, Fe, K

Explanation:

The elements that will form cations readily are Na, Fe and K.

This is because metals are generally electropositive in nature.

  • Cations are positively charged ions that will readily want to lose their electrons.
  • This is opposed to anions that readily wants to gain electrons.
  • An atom that readily loses electrons is said to be electropositive and have a metallic character.
  • Na, Fe and K are metals and will readily lose electrons.

learn more:

Metals and non-metals brainly.com/question/2758034

#learnwithBrainly

const2013 [10]3 years ago
4 0

Answer:

e. Na, Fe, K

Explanation:

The group of elements that will be positive charge ions is metal. You can find metal in the first 2 columns of the periodic table and in the transition area. Natrium/sodium (Na), iron (Fe), and kalium/potassium(K) categorized as metal and they will form positive charge ions.  

On the other hand carbon(C),  oxygen (O), arsenic(As) and bromine(Br) is gas and will form negative charge ions. Gas located on the right side of the periodic table.

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Explanation:

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In a sample of solid ba(no3)2 the ratio of barium ions to nitrate ions is
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One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
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Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

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V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

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V_{small}=\frac{4}{3}\pi (5.01cm)^{3}

V_{small}=5.3*10^{2}cm^{3}

Finally you subtract the two quantities:

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V_{big}-V_{small}=2.4*10^{7}cm^{3}

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