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alexandr402 [8]
2 years ago
10

What is the length of (AB)?

Mathematics
2 answers:
Dafna11 [192]2 years ago
4 0

Answer:

The length of AB is about 5 inches. The length of BC is about 10 inches. I just counted how many squares would be inside the meeting edges. Bc is double AB so that one was easy to figure out.

Step-by-step explanation:) Hope this helps

earnstyle [38]2 years ago
3 0
  • AB = 4 units
  • BC = 8 units
  • perimeter = 2(l+b) = 2(8+4) = 2(12) = 24 units

hope it helps...!!!

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The height of a clocktower is 44 meters. Max, who is standing near the clocktower, casts a 7 meter shadow and is 2 meters tall.
anyanavicka [17]

Answer:

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1 year ago
Describe the transformations required to obtain the graph of the function f(x) from the graph of the function g(x). f(x) = 6 cos
meriva

Answer:

  Vertical stretch by a factor of 6

Step-by-step explanation:

Multiplying the function value by a constant moves its y-coordinate farther away from the x-axis by that factor. It causes a vertical stretch. Here, ...

  the vertical stretch factor is 6

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3 years ago
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second
algol13

Answer:

Therefore the third container contains   \frac{735}{17}\% = 43.23 %  acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

= (V\times \frac{100+55}{100})   cubic unit.

=\frac{155}{100}V  cubic unit.

The amount of acid in first container is

=V\times \frac{25}{100}  cubic unit.

=\frac{25}{100}V  cubic unit.

The amount of acid in second container is

=(\frac{155}{100}V \times \frac{55}{100}) cubic unit.

=\frac{8525}{10000}V cubic unit.

Total amount of acid =(\frac{25}{100}V+\frac{8525}{10000}V) cubic unit.

                                   =(\frac{2500+8525}{10000}V) cubic unit.

                                   =(\frac{11025}{10000}V)cubic unit.

Total volume of mixture =(V+\frac{155}{100}V) cubic unit.

                                       =\frac{100+155}{100}V cubic unit.

                                       =\frac{255}{100}V  cubic unit.

The amount of acid in the mixture is

=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%

=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%

=\frac{735}{17}\%

Therefore the third container contains  \frac{735}{17}\%  acid.

5 0
3 years ago
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Answer:

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Step-by-step explanation:

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