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alexandr402 [8]
2 years ago
10

What is the length of (AB)?

Mathematics
2 answers:
Dafna11 [192]2 years ago
4 0

Answer:

The length of AB is about 5 inches. The length of BC is about 10 inches. I just counted how many squares would be inside the meeting edges. Bc is double AB so that one was easy to figure out.

Step-by-step explanation:) Hope this helps

earnstyle [38]2 years ago
3 0
  • AB = 4 units
  • BC = 8 units
  • perimeter = 2(l+b) = 2(8+4) = 2(12) = 24 units

hope it helps...!!!

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What are the limits of integration if the summation the limit as n goes to infinity of the summation from k equals 1 to n of the
Fofino [41]

Answer:

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Step-by-step explanation:

We want to express \lim_{n\rightarrow \infty} \sum_{k=1}^n\frac{7}{n}(2+\frac{7k}{n})^2 as a integral. To do this, we have to identify \sum_{k=1}^n\frac{7}{n}(2+\frac{7k}{n})^2 as a Riemann Sum that approximates the integral. (taking the limit makes the approximation equal to the value of the integral)

In general, to find a Riemann sum that approximates the integral of a function f over an interval [a,b] we can the interval in n subintervals of equal length and approximate the area (integral) with rectangles in each subinterval and them sum the areas. This is equal to

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\sum_{k=1}^n f(a+k\frac{b-a}{n}) \frac{b-a}{n}.

Now, let's identify this in \sum_{k=1}^n\frac{1}{7n}(2+\frac{7k}{n})^2 .

The integrand is x² so this is our function f. When k=n, the summand should be \frac{b-a}{n}f(b)=\frac{b-a}{n}b^2 because the last selected point is b. The last summand is \frac{7}{n}(9)^2 thus b=9 and b-a=7, then 9-a=7 which implies that a=2.

To verify our answer, note that if we substitute a=2, b=9 and f(x)=x² in the general Riemann Sum, we obtain the sum inside the limit as required.

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