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alexandr402 [8]

2 years ago

10

What is the length of (AB)?

2 answers:

Dafna11 [192]2 years ago

4 0

Answer:

The length of AB is about 5 inches. The length of BC is about 10 inches. I just counted how many squares would be inside the meeting edges. Bc is double AB so that one was easy to figure out.

Step-by-step explanation:) Hope this helps

earnstyle [38]2 years ago

3 0

AB = 4 units
BC = 8 units
perimeter = 2(l+b) = 2(8+4) = 2(12) = 24 units

hope it helps...!!!

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Answer:

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3 years ago

Read 2 more answers

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algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

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$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

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$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

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3 years ago

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Answer:

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