Answer:
9 feet
Step-by-step explanation:
Given:
A prism with a triangular base has a volume of 432 cubic feet.
The height of the prism is 8.
The triangle base has a base of 12 feet.
Question asked:
The height of the triangular base of the prism = ?
solution:
Volume of triangular prism =
Dividing both side by 8
Multiplying both side by 2
Dividing both side by 12
Thus, height of the triangular base of the prism is 9
Answer: hit on them
Step-by-step explanation:
Answer:
look at image
Step-by-step explanation:
you're just making the circle twice as big. so since one of the points of the circle is (0,2) it would now be, (0,4) because 2 x 0 = 0 and 2 x 2 = 4.
Lines parallel to each others only occur when two slopes of equations are same. The definition of parallel lines is:
We are given the equation of a line which is x = -2. For x = a, the equation forms a verical line and has an undefined slope. These below are basic that you may need to learn when learning about the line graph:
- y = a —> horizontal line; slope is 0.
- x = a —> vertical line; slope is undefined.
- For y = a, any a-values would have same x-values. For example, if we are given y = 2 then any domains or x-values can have the range of 2.
- For x = a, any a-values would have same y-values or range.
Back to the question. We want to find the equation of a line that is <u>p</u><u>a</u><u>r</u><u>a</u><u>l</u><u>l</u><u>e</u><u>l</u> to the line x = -2 and <u>p</u><u>a</u><u>s</u><u>s</u><u>e</u><u>s</u><u> </u><u>t</u><u>h</u><u>r</u><u>o</u><u>u</u><u>g</u><u>h</u><u> </u><u>(</u><u>5</u><u>,</u><u>4</u><u>)</u> point. Recall the definition of parallel line that both slopes of equations must equal. Since x = a for any a-values would give an undefined slope. That means our parallel would be x = b.
Because the line passes through (5,4) - for any a-values from x = a would give out the set of all real numbers for range. Therefore the equation of a line is x = 5.
Answer
- The equation of a line that is parallel to x = -2 and passes through (5,4) is x = 5.
I hope this helps! If you have any doubts or questions, don't hestitate to ask in comment! Good luck on your assignment and have a great day!