Answer:
Hi,Can You answer mine too please I really need the answer because I have to pass it tomorrow morning at my 1st class:(can you please check my question I'll mark you BRAINLIEST:)I hope you can help me:)
Step-by-step explanation:
about your question I'll just put it in the comment section:)
Answer:
The mean is also increased by the constant k.
Step-by-step explanation:
Suppose that we have the set of N elements
{x₁, x₂, x₃, ..., xₙ}
The mean of this set is:
M = (x₁ + x₂ + x₃ + ... + xₙ)/N
Now if we increase each element of our set by a constant K, then our new set is:
{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}
The mean of this set is:
M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N
M' = (x₁ + x₂ + ... + xₙ + N*k)/N
We can rewrite this as:
M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N
and (x₁ + x₂ + ... + xₙ)/N was the original mean, then:
M' = M + (k*N)/N
M' = M + k
Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.
Since it is a square, the diagonals are congruent. If a square is split like this, it becomes two congruent right triangles. The relationship between the sides and hypotenuse is a 1:

ratio. So if the diagonal of a square is 14 cm, then the side length would be 14/

, which is approximately 9.899. I don't understand what the answer choices are, but you should be able to square root the numbers to determine the answer.