D(x) = 32x......ur range will be ur d(x) values and the domain will be ur x values.....where d(x) = total distance and x = gallons.
So we already know that ur car's fuel tank holds 17 gallons....therefore, ur domain has to be 17 gallons or less...but it cant be negative.
so ur domain is : 0 < = x < = 17
now for ur range....since the car only holds 17 gallons....d(x) = 32(17) = 544 miles....thats the farthest it can go...therefore it can go from 0 to 544 miles....so ur range is : 0 < = d(x) < = 544
or u could write it as : domain = (0,17) with 0 representing an empty tank and 17 representing a full tank.....and ur range = (0,544) with 0 representing 0 miles driven and 544 representing 544 miles driven
Answer:
The approximate mass of the brain of a mouse is 2 grams
Step-by-step explanation:
The correct question in the attached figure
Let
B -----> the approximate mass B of the brain in grams
m ----> the mass of a mammal's brain in grams
we know that
----> given problem
we have
substitute in the formula above
Remember that
![(64)^{\frac{2}{3}}=\sqrt[3]{(64)^2}=\sqrt[3]{(4^{3})^2}=\sqrt[3]{(4^{6})}=4^{2}=16](https://tex.z-dn.net/?f=%2864%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B%2864%29%5E2%7D%3D%5Csqrt%5B3%5D%7B%284%5E%7B3%7D%29%5E2%7D%3D%5Csqrt%5B3%5D%7B%284%5E%7B6%7D%29%7D%3D4%5E%7B2%7D%3D16)
IJ=x-4
JK=5x+12
IK=9x-19
IJ+JK=IK
(x-4)+(5x+12)=(9x-19)
x-4+5x+12=9x-19
6x+8=9x-19
6x+8-6x+19=9x-19-6x+19
27=3x
3x=27
3x/3=27/3
x=9
IJ=x-4=9-4→IJ=5
JK=5x+12=5(9)+12=45+12→JK=57
IK=9x-19=9(9)-19=81-19→IK=62
Answer: Option B. IJ=5, JK=57, IK=62
Answer:
y = (1/2)x + 2
Step-by-step explanation:
Find the slope:
Take the rise over run to find this- For every unit it goes up, it goes two units across, so it will be (1/2)
Find the y-intercept:
This is the value of y where the line intersects the y-axis- (0,2), so 2
Substitute these values in for m and b:
y = mx + b
y = (1/2)x + 2
Hope that helps! :)
<h3>
Answer: 32</h3>
Explanation:
This is a 30-60-90 triangle as shown by the angles. These types of triangles have their shortest leg opposite the smallest angle, and the connection between the short and long legs is
long = short*sqrt(3)
We see that the long leg is 16*sqrt(3) units long, which must mean the short leg is 16 units. This doubles to 32 when we go from short leg to hypotenuse
hypotenuse = short*2
