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2 years ago

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The length of a rectangular poster is 9 more inches than two times its width. The area of the poster is 161 square inches. Solve

for the dimensions (length and width) of the poster.

2 answers:

irinina [24]2 years ago

8 0

Answer:

<u>Width = 7 inches</u>

<u>Length = 23 inches</u>

Step-by-step explanation:

Let :

length = 2x + 9
width = x

Equating to area :

(2x + 9)(x) = 161
2x² + 9x = 161
2x² + 9x - 161 = 0
2x² - 14x + 23x - 161 = 0
2x(x - 7) + 23(x - 7) = 0
x - 7 = 0
x = 7

Dimensions are :

<u>Width = 7 inches</u>
Length = 2(7) + 9
<u>Length = 23 inches</u>

BaLLatris [955]2 years ago

7 0

Answer:

Length: 23 inches

Width: 7 inches

Explanation:

Width: w

Length: 2w + 9

<h3>Area of rectangle: Length × Width</h3>

(2w + 9) × (w) = 161

2w² + 9w - 161 = 0

2w² + 23w - 14w -161 = 0

w(2w + 23) -7(2w +23) = 0

w = 7, -11.5

As <u>length measure cannot be negative</u>. Width is +7 inches

Length: 2w + 9 = 2(7) + 9 = 14 + 9 = 23

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