The length of a rectangular poster is 9 more inches than two times its width. The area of the poster is 161 square inches. Solve for the dimensions (length and width) of the poster.
2 answers:
Answer:
<u>Width = 7 inches </u>
<u>Length = 23 inches </u>
Step-by-step explanation:
Let :
Equating to area :
(2x + 9)(x) = 161 2x² + 9x = 161 2x² + 9x - 161 = 0 2x² - 14x + 23x - 161 = 0 2x(x - 7) + 23(x - 7) = 0 x - 7 = 0 x = 7
Dimensions are :
<u>Width = 7 inches </u> Length = 2(7) + 9 <u>Length = 23 inches </u>
Answer:
Length: 23 inches
Width: 7 inches
Explanation:
<h3>Area of rectangle: Length × Width</h3>
w(2w + 23) -7(2w +23) = 0 As <u>length measure cannot be negative</u>. Width is +7 inches
Length: 2w + 9 = 2(7) + 9 = 14 + 9 = 23
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