Answer:

Step-by-step explanation:
We are given that


y(0)=0
y'(0)=1
By comparing with

We get


q(x)=0
p(x),q(x) and g(x) are continuous for all real values of x except 3.
Interval on which p(x),q(x) and g(x) are continuous
and (3,
By unique existence theorem
Largest interval which contains 0=
Hence, the larges interval on which includes x=0 for which given initial value problem has unique solution=
Answer:
corollary,postulate,theorem,definition
Answer:solve for x
-3x+5y=-15
Add -5y to both sides
-3x+5y+-5y=-15+-5y
-3x=-5y-15
Divide both sides by -3
-3x/-3=-5y-15/-3
x= 5/3 y +5
I hope that's help!
Step-by-step explanation: plz give brainlist
We will round both numbers:-
9.1 = 9
11.8 = 12
Now we will multiply these 2 numbers to get our answer.
9 × 12 = 108
So, 9.1 ÷ 11.8 is ABOUT 108.
Hope I helped ya!!!!!!!