A system of equations that could be used to determine the number of cans of soup purchased and the number of frozen dinners purchased is:
350x + 500y = 4800
y = 2x
<h3>Definition of variables </h3>
x = number of cans of soup purchased
y = number of frozen dinners purchased.
<h3>Simultaneous equations </h3>
The system of equations are known as simultaneous equations. Simultaneous equations are group of equations that have to be solved together in order to determine the required values.
<h3>Methods used to solve simultaneous equations </h3>
- Elimination method
- Graph method
- Substitution method
To learn more about simultaneous equations, please check: brainly.com/question/25875552
Answer:
D 6
Step-by-step explanation:
4/1 / 8/12
4/1 * 12/8
48 / 8 = 6
Answer:

Step-by-step explanation:
The dealing of the cards can be seen in the following way:
We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in
ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in
ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in
. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in
ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in
. And again, we have to choose which ones are the hidden ones, which can be chosen in
ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in
ways. And choosing which ones are the hidden ones for this player can be done in
ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

No because adding the two fives will give you a 10 and 10 is greater than 3
Answer: A.
Step-by-step explanation: