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zepelin [54]
2 years ago
13

A baseball stadium sells game tickets for $8 each and has a capacity of 200 people. The function M(x) = 8x represents the amount

of money the baseball stadium makes from ticket sales, where x is the number of spectators. What would be the most appropriate domain for the function? (1 point) Whole numbers that are multiples of 8 Whole numbers less than or equal to 200 All whole numbers All real numbers
Mathematics
1 answer:
ollegr [7]2 years ago
8 0

The domain of the function is whole numbers less than or equal to<em> </em>200

The given parameters;

  • cost of the game tickets = $8 per spectator
  • maximum capacity of the stadium = 200

The function for the amount of money the baseball stadium makes from ticket sales is given as;

M(x) = 8x

where;

  • x  is the number of spectators

Since the maximum capacity of the stadium is 200, the number of spectators should be less or equal to 200.

x ≤ 200

Thus, the domain of the function is whole numbers <em>less than</em> or <em>equal to </em>200

Learn more here: brainly.com/question/16892163

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What is 2.03 written in words and numbers?
Rudiy27
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5 0
3 years ago
Read 2 more answers
What is the result of substituting for y in the bottom equation<br> y=x+3<br> y=x^2+2x-4
8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

<em><u>Solution:</u></em>

Given that,

y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4  ----- eqn 2

<em><u>We have to substitute eqn 1 in eqn 2</u></em>

x + 3 = x^2 + 2x - 4

\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0

\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}

x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}

x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925

Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

y = 5.1925

Substitute x = -3.1925 in eqn 1

y = -3.1925 + 3

y = -0.1925

Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

6 0
4 years ago
Is 4y - 8 &gt; 10 true?
steposvetlana [31]

4y-8>10

Add 8

4y-8+8>10+8

4y>18

Now divide both sides by 4

4y/4 > 18/4

y>9/2


Now let's see if it will be true

Replace y by its value

4(9/2)-8>10

36/2 -8 > 10

18-8 > 10

10 > 10

That's false because 10 can not smaller than 10

so it should be = instead


Answer : False


I hope that's help:)

7 0
3 years ago
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