The fourth term in the expansion of the binomial (2x + y2)5 is

1 answer:

4 0

(2x+y2)5 = 32x5 + 160x4y + 320x3y2 + 320x2y3 + 160xy4 + 32y5

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Andrews [41]

Answer:

6 $x^{2}$ - 19x + 15

Step-by-step explanation:

(2x - 3) (3x - 5)

2x(3x-5) - 3 (3x-5)

6 $x^{2}$ - 10x - 3 (3x - 5)

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