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3 years ago

The fourth term in the expansion of the binomial (2x + y2)5 is

Mathematics

1 answer:

Irina-Kira [14]3 years ago

4 0

(2x+y2)5 = 32x5 + 160x4y + 320x3y2 + 320x2y3 + 160xy4 + 32y5

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Solve for the value of v: V+27=117

Fudgin [204]

V+27=117
Subtract 27 to 117:
v=90

7 0

2 years ago

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I need help!!! ill give brain-list!!!

In-s [12.5K]

Answer:

8 hours worked, 64 dollars

56 dollars, 7 hours worked

themepark:

5 hours worked, 45 dollars

6 hours worked, 54 dollars

8 hours worked, 72 dollars

working at the themepark earns 5 extra dollars when they work for 5 hours.

5 0

3 years ago

The principal wants to buy 8 pencils for every student at her school. If there are 859 students, how

nordsb [41]

Answer: 6872

Step-by-step explanation:

8 x 859 = 6872

6 0

3 years ago

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Dana saved 450 for food for her upcoming vacation. The breakfast was included with their hotel, but lunch and dinner are not. Wh

zzz [600]

Answer:

$10d + 40r \leq 450$

Step-by-step explanation:

Given

$Savings = 450$

$Dana\ Cooks, d = 10$

$Restaurant, r = 40$

Required

Represent this as an inequality

When Dana cooks;

$Cost\ per\ meal = 10$

$Cost\ per\ d\ meals = d * 10$

$Cost\ per\ d\ meals = 10d$

At Restaurant

$Cost\ per\ meal = 40$

$Cost\ per\ r\ meals = 40 * r$

$Cost\ per\ r\ meals = 40 r$

Add these two results:

$Result = 10d + 40r$

<em>To represent as an inequality, the above result must be less than or equal to Dana's total savings</em>

i.e.

$10d + 40r \leq 450$

3 0

3 years ago

What is the length of side TS?

balandron [24]

Step-by-step explanation:

In order to find the length of side TS, first we need to find the length of side TR which is perpendicular to side QS.

By Geometric mean property:

${TR} = \sqrt{6 \times 12} \\ \therefore \: {TR} = \sqrt{6 \times 6 \times 2} \\ \therefore \: {TR} = 6\sqrt{2} \\ \\ In \: right \: \triangle \: TRS: \\ TS^2 = TR^2 + RS^2 \\ \therefore \: (3x)^{2} = {(6 \sqrt{2}) }^{2} + {(12)}^{2} \\ \therefore \: 9x^{2} = 72 + 144 \\ \therefore \: 9x^{2} =2 1 6 \\ \therefore \: x^{2} = \frac{2 1 6}{9} \\ \therefore \: x^{2} =24 \\ \therefore \: x = \sqrt{24} \\ \therefore \: x = 4.89897949 \\ \therefore \: x \approx \: 4.9 \\ \therefore \: 3x = 3 \times 4.9 \\ \therefore \: 3x =14.7 \\ \huge \red{ \boxed{\therefore \: TS = 14.7 \: units}}$

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3 years ago

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