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2 years ago

AYUDDAAA, ES EXAMEEEEN

Mathematics

2 answers:

madam [21]2 years ago

4 0

Answer:

it's corect

Step-by-step explanation:

just change the subject it is not mathematics

olganol [36]2 years ago

4 0

Answer:

correct

Step-by-step explanation:

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Without actually carrying out the steps of multiplication, determine whether the product of 15.1 and 0.9 will be larger or small

yan [13]

Answer: Smaller

Step-by-step explanation: The product of 15.1 and 0.9 will be smaller than 15.1. This is because 0.9 is smaller than 1 and since 15.1 * 1 is 15.1, we know that anything smaller than 1 will result in the product of it and 15.1 being smaller.

Would appreciate brainly <3

7 0

2 years ago

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A surveying team needs to find the distance across a canyon. They decide to locate two point, A and B, on one side of the canyon

balandron [24]

Answer:

B). About 109 meters

6 0

3 years ago

there are 8 students on the minibus. five of the students are boys. what fraction of the students are boy

meriva

Students on the minibus = 8
students that are boys = 5
fraction of the student that are boys = ?
we can write fraction as the numerator and denominator so here the fraction of boys students is = 5/8
this fraction means and shows that there are 5 students are boys from 8 students.

3 0

3 years ago

19 degrees more than three times the measurement of v

Vladimir [108]

(3v+19)°
the answer to the question

3 0

3 years ago

Astronomers treat the number of stars X in a given volume of space as Poisson random variable. The density of stars in the Milky

cupoosta [38]

Answer:

Explained below.

Step-by-step explanation:

The random variable X is defined as the number of stars in a given volume of space.

$X\sim \text{Poisson}\ (\lambda=1)$

The probability mass function of X is:

$p_{X}(x)=\frac{e^{-\lambda}\lambda^{x}}{x!}$

(7)

Compute the probability of exactly two stars in 16 cubic light-years as follows:

$P(X=2)=\frac{e^{-1}\times 1^{2}}{2!}=\frac{e^{-1}}{2}=\frac{0.36788}{2}=0.18394\approx 0.184$

(8)

Compute the probability of three or more stars in 16 cubic light-years as follows:

$P(X\geq 3)=1-P(X$

(9)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in 4 cubic light years there will be, 4 × (1/16) = (1/4) stars.

(10)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in t cubic light years there will be, [t × (1/16)] stars.

7 0

3 years ago