Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
Answer:
0.0055 or 11/2000
Step-by-step explanation:
You could have multiplied it by 100 moving the decial poitn to the left 2 place. Or converted it to a fraction then divided the numerator by the denominator.
Hope this helps!!
The answer is 3. 20/2=10 10-7=3
Answer:
so one side right?
Step-by-step explanation:
Answer:
1100 field-side tickets and 4500 end-zone tickets.
Step-by-step explanation:
Let x represent number of field side tickets and y represent number of end-zone tickets.
We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:
![x+y=5600...(1)](https://tex.z-dn.net/?f=x%2By%3D5600...%281%29)
We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
Cost of x field side tickets would be
and cost of y end-zone tickets would be
.
The total amount of money received for the tickets was $134000. We can represent this information in an equation as:
![40x+20y=134000...(2)](https://tex.z-dn.net/?f=40x%2B20y%3D134000...%282%29)
Upon substituting equation (1) in equation (2), we will get:
![40x+20(5600-x)=134000](https://tex.z-dn.net/?f=40x%2B20%285600-x%29%3D134000)
![40x+112000-20x=134000](https://tex.z-dn.net/?f=40x%2B112000-20x%3D134000)
![20x+112000=134000](https://tex.z-dn.net/?f=20x%2B112000%3D134000)
![20x+112000-112000=134000-112000](https://tex.z-dn.net/?f=20x%2B112000-112000%3D134000-112000)
![20x=22000](https://tex.z-dn.net/?f=20x%3D22000)
![\frac{20x}{20}=\frac{22000}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B20x%7D%7B20%7D%3D%5Cfrac%7B22000%7D%7B20%7D)
![x=1100](https://tex.z-dn.net/?f=x%3D1100)
Therefore, 1100 field side tickets were sold.
Upon substituting
in equation (1), we will get:
![y=5600-1100](https://tex.z-dn.net/?f=y%3D5600-1100)
![y=4500](https://tex.z-dn.net/?f=y%3D4500)
Therefore, 4500 end-zone tickets were sold.