the answer to a division problem is 23. How can you change the problem so that it has a remainder of 3?
2 answers:
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Answer:
Step-by-step explanation:
-5/2 × (3x + 4) < 6x - 3x
-15/2x - 10 < 3x
-15x - 20 < 6x
-15x - 6x < 20
-21x < 20
<u>x</u><u> </u><u>></u><u> </u><u>-</u><u>2</u><u>0</u><u>/</u><u>2</u><u>1</u>
= 9n + 63
generate the first few terms using the recursive equation
f(1) = 72
f(2) = 72 + 9 = 81
f(3) = 81 + 9 = 90
f(4) = 90 + 9 = 99
the sequence is 72, 81, 90, 99, .....
This is an arithmetic sequence whose n th term formula is
=
+ (n - 1 )d
where is the first term and d the common difference
d = 99 - 90 = 90 - 81 = 81 - 72 = 9 and = 72
= 72 + 9(n - 1) = 72 + 9n - 9 = 9n + 63 ← explicit formula