Question

Find the equation of circle (5,1) diameter 4 square root 5​

Answer 1

Answer:

$(x-5)^2+(y-1)^2=20$

Step-by-step explanation:

Equation of a circle

$(x-a)^2+(y-b)^2=r^2$

(where (a, b) is the center and r is the radius)

Given:

• center = (5, 1)
• diameter = 4√5

Diameter = 2r (where r is the radius)

⇒ r = 4√5 ÷ 2 = 2√5

Substituting these values into the equation:

$\implies (x-5)^2+(y-1)^2=(2\sqrt{5})^2$

$\implies (x-5)^2+(y-1)^2=20$