Answer:
4/3
Step-by-step explanation:
The probability that the first two electric toothbrushes sold are defective is 0.016.
The probability of an event, say E occurring is:

Here,
n (E) = favorable outcomes
N = total number of outcomes
Let X = the number of defective electric toothbrushes sold.
The number of electric toothbrushes that were delivered to a store is n = 20.
The number of defective electric toothbrushes is x = 3.
The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:


The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:


Compute the probability that the first two electric toothbrushes sold are defective as follows:
P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.
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I found this online I hope it helps a little if not, then sorry.
Answer is to your question is A
Answer:
The answer should be either 2(p+10) or 2p + 20
Step-by-step explanation:
just simplify.