Find the slope of a line perpendicular to 3x+y=15 ,-1/3, 5, -3, 1/3

1 answer:

8 0

So in the proper form, the equation would by y = 3x + 15. This means it has a slope of 3. Perpendicular lines have slopes that are negative reciprocals. The negative reciprocal of 3 (or 3/1) is -1/3.

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1. 5 x 4 = A. 20

$\frac{2}{5} \times 25 = 2 \times 5 = 10$