Answer:
First, determine how many standard deviations above the mean one would have to be to be in the 75th percentile. This can be found by using a z table and finding the z associated with 0.75. The value of z is 0.674. Thus, one must be .674 standard deviations above the mean to be in the 75th percentile
Answer:
x=-1
Step-by-step explanation:
54x+64=49x+59
subtract 64
54x=49x-5
subtract 49x
5x=-5
divide by 5
x=-1
3x-17+x+40+2x-5=180
6x=162
x=27
(From left to right) 67,64, 49
Answer:
45
Step-by-step explanation:
45 > 42 but < 47 and it's a multiple of 3 and 5
