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erastovalidia [21]
2 years ago
7

The volume of a cone is 3rx? cubic units and its height is x units. Which expression represents the radius of the cone's base, i

n units?
O 3πx
O 6πx
O 3πx2
O 9πx2​
Mathematics
1 answer:
Marianna [84]2 years ago
3 0

Answer:

It is given that the volume of a cone = 3\pi x^3 cubic units

Volume of cone with radius 'r' and height 'h' = \frac{1}{3}\pi r^2h

Equating the given volumes, we get

3\pi x^3=\frac{1}{3}\pi r^2h

r^2h=3 × 3x^3

r^2h=9 x^3

It is given that the height is 'x' units.

Therefore, r^2x=9x^3

r^2=9x^2

Therefore, r=3 x

So, the expression '3 x' represents the radius of the cone's base in units.

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42=Wf×64 (what fraction)
Dmitry [639]
So basically 42=x times 64 or 42=64x where you want x to be represented as a fraction so just don't simplify as much

42=64x
divide both sdies by 64
42/64=64/64x
42/64=1x
x=42/64
simplify
42/64=21/32

the answer is 21/32 in simplest form
7 0
3 years ago
Shay mal e 8 2/3 cups of snacks mix she puts all the snack mix into plastic bags she puts 1/3 cup of the snack mix in each bag h
AnnyKZ [126]

Answer:

She needs 26 plastic bags.

Step-by-step explanation:

Given:

Amount of cups of snacks mix = 8 2/3

Rewriting 8 2/3 we get,

Amount of snacks mix = \frac{26}{3}

Number of Cups in each bag = \frac{1}{3}

She puts all the snacks mix in plastic bags

We need to find the number of plastic bags required to put all the snacks mix

Let number of plastic bag be x.

hence we can say that Number of Cups in each bag multiplied by number of plastic bag is equal to  Amount of snacks mix.

\frac{1}{3}x=\frac{26}{3}\\\\x= \frac{26\times3}{3\times1} =26

Hence total number of plastic bags she needs is 26.

6 0
3 years ago
The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. Th
finlep [7]

Question:

The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. The top one is labeled Class. Minimum at 70, Q1 at 74, median at 83, Q3 at 92, maximum at 100. The bottom box plot is labeled Exam. Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95. Which of the following best describes the information about the medians? (1 point) Group of answer choices

•The exam outlier at 60 makes the IQR narrower and the median higher.

•The class data is more evenly spread, which pulls its median down.

•The class median is lower than the exam median.

•The class Q3 is higher than the exam Q3.

Answer:

•The class Q3 is higher than the exam Q3.

Step-by-step explanation:

In the question we have two box plots

a) Box plots for class is given as

Minimum at 70, Q1 at 74, median at 83, Q3 at 92,

b) Box plots for exam is given as Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95.

When we compare the median of the class which is 83 and the median of the exam plots 87, we can see that the median of the exam is higher than the median of the class, hence the option

"•The class median is lower than the exam median". is wrong.

From the options given, the only correct option which best describes the information about the medians is

"•The class Q3 is higher than the exam Q3".

This is because when we compare the Q3 of the class which is 92 to the Q3 of the box which is 91 , we can see that the class Q3 is higher than the box Q3 hence the option is correct.

8 0
3 years ago
-3p + 8 = -13 <br><br> HELLLLPP
ella [17]

Answer:

p=-7     :)

Step-by-step explanation:

-13-8=3p

-13+(-8)=3p

-21=3p

  ÷3

-7=p

5 0
3 years ago
Help Me! ASAP! Determine whether each equation has no solution, one solution or infinitely many solutions. Choose No Solution, O
ladessa [460]

Answer:

Step-by-step explanation:

(1). One solution

(2). Infinitely Many Solutions

(3). One solution

(4). No Solution

7 0
3 years ago
Read 2 more answers
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