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2 years ago

Help pls!! I don’t understand

Mathematics

1 answer:

Debora [2.8K]2 years ago

7 0

$\bold{ANSWER:}$
x = 55

$\bold{SOLUTION:}$

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Given a cube with a volume of 27 cm3, what is the volume of a square pyramid that can fit perfectly inside the cube?

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Students water a plant with the same amount of water for 28 days, if the students use a total of 23.8 L of water over the 28 day

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3 years ago

The mean distance of the Moon from Earth is 2.39x10^5 miles. Assuming that the orbit of the Moon around Earth is circular and th

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2291,94 mph

Step-by-step explanation:

To solve this we need to consider the distance 2.39x10^5 miles as the distance between the center of the earth and the center of the moon, if not we would need to know the radius of the earth and the moon.

If the distance is 2.39x10^5 miles, the orbit is = 2.Pi.(2.39x10^5) miles=1501681.288miles

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3 years ago

Find the volume of a pyramid with a square base, where the perimeter of the base is 8.2\text{ cm}8.2 cm and the height of the py

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Answer:

$V=18.2cm^3$

Step-by-step explanation:

The volume of the pyramid is given by:

$V=\frac{A_{b}h}{3}$

where $A_{b}$ is the area of the base and $h$ is the height.

We know that the height is:

$h=13cm$

Thus we need to find the area of the square at the base.

The perimeter of the square is:

$p=8.2cm$

this means that the length of the sides of the square is :

$l=\frac{p}{4}\\ \\l=\frac{8.2cm}{4}\\ \\l=2.05cm$

Now we can find the area of the base which the area of the square:

$A_{b}=l^2\\A_b=(2.05cm)^2\\A_b=4.2025cm^2$

and finally we find the volume:

$V=\frac{A_{b}h}{3}$

$V=\frac{(4.2025cm^2)(13cm)}{3}\\ \\V=\frac{54.6325cm^3}{3}\\ \\V=18.2108cm^3$

Which rounded to the nearest tenth of a cubic centimeter is: $V=18.2cm^3$

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3 years ago