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il63 [147K]
3 years ago
15

Help pls!! I don’t understand

Mathematics
1 answer:
Debora [2.8K]3 years ago
7 0
\bold{ANSWER:}
x = 55

\bold{SOLUTION:}

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Solve for a: am=n+p <br><br> Help me
ss7ja [257]

Answer:

a = (n + p)/m

Step-by-step explanation:

just divide by m on both sides

hope this helped!

6 0
3 years ago
A cylindrical well has a radius of 10 feet and a height of 15 feet.what volume of water will it take to fill in the well?
horsena [70]
The volume of the well...
V ≈ 4712.39
6 0
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What is the area of this parallelogram?
Alex Ar [27]
Formula for area of parallelogram:
A= bh
Where b is the length of base and h is the height.
Here b=2.3+4.5 = 6.8 cm
and h= 4.5 cm
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7 0
3 years ago
In a game, Janeesa started with 0 points. She then earned 50 points, lost 80 points and earned 10 points. Which number line show
umka2103 [35]

Answer:

-20

Step-by-step explanation:

If Jeneesa started with, 0 points and she earned 50, then she would have 50. If she lost 80 points, she would go into the negatives. She would be at -30, and when she earned 10 more points, she would be at -20.

I don't know what your options look like, but look at the one(s) with -20 at the end and figure out what one best fits my explanation (and the numbers I use)!

3 0
3 years ago
9x² - 12x + 4 <br><br>pls need ans.​
kolezko [41]

Step-by-step explanation:

\tt{9 {x}^{2}  - 12x + 4}

Here, the second order of polynomial ax² + bx + c is factorized and expressed as the product of two linear factors. First, we have to find the two numbers that adds to 12 and if we multiply those numbers , we get 36 ( The two numbers should be 6 and 6 ).

⟶ \tt{9 {x}^{2}  - (6 + 6)x + 4}

⟶ \tt{9 {x}^{2}  - 6x - 6x + 4} { Distribute x through the parentheses )

⟶ \tt{ \underbrace{9 {x}^{2}  - 6x}} \:  -  \underbrace{6x + 4}

⟶ \tt{3x(3x - 2) - 2(3x - 2)}

⟶ \tt{(3x - 2)(3x - 2)}

⟶ \tt{ {(3x - 2)}^{2} }

\pink{ \boxed{ \boxed{ \tt{ Our \: final \: answer :  \boxed{ \underline{ \tt{{(3x - 2)}^{2} }}}}}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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4 0
3 years ago
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