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Pavel [41]
3 years ago
12

Solve 81^x = 27^^^x + 2. A. x = 1 B. x = 2 C. x = 5 D. x = 6

Mathematics
2 answers:
mart [117]3 years ago
8 0

For this case we must solve the following equation:

81 ^ x = 27^{x + 2}

We rewrite:

81 = 3 ^ 4\\27 = 3 ^ 3

Then, replacing:

3^{4x} = 3^{3 (x + 2)}

For the bases to be equal then it must be fulfilled that:

4x = 3 (x + 2)\\4x = 3x + 6\\4x-3x = 6\\x = 6

Answer:

x = 6

Option D

omeli [17]3 years ago
6 0

Answer:

x=6

Step-by-step explanation:

81^x=27^(x+2)

3^4x=3^3(x+2)

4x=3(x+2)

4x=3x+6

x=6

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natali 33 [55]

Below is the pseudocode of the "test" algorithm:

algorithm "test"

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A: VECTOR [1..3,1..3] OF WHOLE

C, L, M: WHOLE

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final algorithm

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II. A is an order 3 matrix.

III. At the end of its execution, the algorithm prints the smallest value of the matrix.

IV. At the end of its execution, the algorithm prints the largest value of the matrix.

Now, mark the alternative that presents the CORRECT answer.

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3 years ago
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For any question comment me

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