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Pavel [41]
3 years ago
12

Solve 81^x = 27^^^x + 2. A. x = 1 B. x = 2 C. x = 5 D. x = 6

Mathematics
2 answers:
mart [117]3 years ago
8 0

For this case we must solve the following equation:

81 ^ x = 27^{x + 2}

We rewrite:

81 = 3 ^ 4\\27 = 3 ^ 3

Then, replacing:

3^{4x} = 3^{3 (x + 2)}

For the bases to be equal then it must be fulfilled that:

4x = 3 (x + 2)\\4x = 3x + 6\\4x-3x = 6\\x = 6

Answer:

x = 6

Option D

omeli [17]3 years ago
6 0

Answer:

x=6

Step-by-step explanation:

81^x=27^(x+2)

3^4x=3^3(x+2)

4x=3(x+2)

4x=3x+6

x=6

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What is between 50 and 100
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6 0
3 years ago
Read 2 more answers
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Dmitriy789 [7]

Answer:

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Answer:

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