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aliya0001 [1]
1 year ago
9

Find the surface area of the triangular prism shown.

Mathematics
2 answers:
Alinara [238K]1 year ago
5 0

Answer:

A=2AB+(a+b+c)h

AB=s(s﹣a)(s﹣b)(s﹣c)

s=a+b+c

2

Solving for A

A=ah+bh+ch+1

2﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=10·4+6·4+8·4+1

2·﹣104+2·(10·6)2+2·(10·8)2﹣64+2·(6·8)2﹣84=144

i think

Step-by-step ex planation:

kherson [118]1 year ago
3 0
You got this !! …………….

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250 is 1.5cm. How thick is 400 pages
svetlana [45]

Answer: 2.4 cm

Step-by-step explanation:

1.5 divided by 250 gives that each page is .006cm. 400 times .006 is 2.4cm

7 0
3 years ago
Find the value of x<br><br> HELP please !
Makovka662 [10]

Answer:

116+34+x=180

150+x=180

x=180-150

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5 0
3 years ago
Consider the following initial-value problem. Y'' − 5y' = 8e4t − 4e−t, y(0) = 1, y'(0) = −1 find ℒ{f(t)}, for f(t) = 8e4t − 4e−t
Nataliya [291]

The <em>Laplace</em> transform of the <em>non-homogeneous second order differential</em> equation is \mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}.

<h3>How to determine the Laplace transform of a non-homogeneous second order differential equation </h3>

A <em>Laplace</em> transform is a <em>frequency-based algebraic</em> substitution method used to determine the solutions of <em>differential</em> equations in a quick and efficient manner.

In this question we shall use the following <em>Laplace</em> transforms:

\mathcal {L} \{f(t) + g(t)\} = \mathcal {L} \{f(t)\} + \mathcal {L}\{g(t)\}   (1)

\mathcal {L} \{\alpha\cdot f(t)\} = \alpha\cdot \mathcal {L} \{f(t)\}   (2)

\mathcal{L} \left\{y^{(n)} \right\} = s^{n}\cdot \matcal {L}\{f(t)\}-s^{n-1}\cdot y(0) -...-y^{(n)}(0)   (3)

\mathcal {L} \{e^{-a\cdot t}\} = \frac{1}{s+a}   (4)

Now we proceed to derive an expression fo the <em>Laplace</em> transform of the solution of the <em>differential</em> equation:

y'' -5\cdot y' = 8\cdot e^{4\cdot t}-4\cdot e^{-t}

s^{2}\cdot \mathcal {L}\{f(t)\}-5\cdot y(0) - y'(0) - 5\cdot s \cdot \mathcal {L} \{f(t)\} +5\cdot y(0) = \frac{8}{s-4}-\frac{4}{s+1}

\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}

The <em>Laplace</em> transform of the <em>non-homogeneous second order differential</em> equation is \mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}. \blacksquare

To learn more on Laplace transforms, we kindl invite to check this verified question: brainly.com/question/2272409

5 0
2 years ago
a garden measuring 10 feet by 12 ft is to have a uniform width pedestrian pathway installed all the way around it, increasing th
tigry1 [53]

Answer:

Area of pathway = 135 ft

Width of the pathway = 5 ft

Step-by-step explanation:

255 ft = 15 ft times 17 ft

15 ft minus 10 ft =5 ft

17 ft minus 12 ft =5 ft

8 0
2 years ago
(a+b)^3 ///////////////////////////
stepan [7]

Answer:

What is the question you are asking?

3 0
2 years ago
Read 2 more answers
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