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slamgirl [31]
2 years ago
13

What are the intercepts of the graphed function?

Mathematics
1 answer:
shepuryov [24]2 years ago
3 0
The answer is YON. x-intercept = (-1, 0)
y-intercept = (0, -3)

When you are writing an intercept, the other variable is 0.

For x-intercepts: (x, 0)
For y-intercepts: (0, y)
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Simplify 27^2.<br><br> please (thxx)
adoni [48]

Answer:

729

Step-by-step explanation:

Raise 27 to the power of 2.

729

4 0
3 years ago
Anyone answering the coordinates subtraction can get there 100 points here.
Sholpan [36]

Answer:

c = -6

d = 2

Step-by-step explanation:

After reflection about the x-axis:

A --> A'

(x,y) --> (x,-y)

(2,3) --> (2,-3)

(4,3) --> (4,-3)

(2,6) --> (2,-6)

After translation:

(2 + c, -6 + d) --> (-4, -4)

2+c = -4

c = -6

-6+d = -4

d = 2

3 0
3 years ago
Read 2 more answers
I need help plss. I will give you a lot of points I promise
Alekssandra [29.7K]
Slope=0.005/2.000=0.002
p - intercept = 974/1 = 974.00000
n- intercept = 974/-404 = 487/-202 = -2.41089


Oh and it is ok if you don’t have a lot of points I am great full for the points you are giving me and the answer is C)13,094 and can I have the brainliest since the other guy clearly did not answer the question right I only have one brainliest ☺️
8 0
3 years ago
Read 2 more answers
Giúp mình với mình không biết làm
Vladimir [108]
Can you translate so I can help you out
4 0
2 years ago
The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the
Temka [501]
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.

2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
7 0
2 years ago
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