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Masteriza [31]
2 years ago
14

suzan normally earns $300 a month working part time at an appliance store. she worked 17 hours extra over a holiday weekend, for

which she was paid $24.50 per hour. what did she earn in that month?
Mathematics
1 answer:
Harman [31]2 years ago
6 0

Answer:

she earned 716.5

Step-by-step explanation:

17x24.50 = 416.5

416+300 = 716.5

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How do u solve y pluse 4 pluse 3(y pluse 2)
lesya [120]
Y + 4 + 3(y+2)    first distribute the 3
y + 4 + 3y + 6     then add like terms
4y + 10

therefore your answer should be  4y + 10
3 0
3 years ago
Read 2 more answers
If ac =14 find the value of x then find ab and bc
Igoryamba

Answer:

If B is between A and C, AB = x, BC = 2x + 2, and AC = 14, find the value of x. Then find AB and BC.

Step-by-step explanation:

AB=x

BC = 2x + 2BC=2x+2

AC =14AC=14

Required

Determine x, AB and BC.

Since B is between A and C;

AB + BC = ACAB+BC=AC

Substitute x for AB; 2x + 2 for BC and 14 for AC

x + 2x + 2 = 14x+2x+2=14

3x + 2 = 143x+2=14

Collect Like Terms

3x = 14 - 23x=14−2

3x = 123x=12 '

x = \frac{12}{3}x=

3

12

x = 4x=4

Substitute 4 for x in

AB = xAB=x

BC = 2x + 2BC=2x+2

AB = 4AB=4

BC = 2(4) + 2BC=2(4)+2

BC = 8 + 2BC=8+2

BC = 10BC=10

3 0
2 years ago
Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

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Answer:

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Step-by-step explanation:

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