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salantis [7]
2 years ago
7

Which of the following are statistical questions? Select all that apply.

Mathematics
1 answer:
Olegator [25]2 years ago
5 0
The answers are a b c d e or all of them except the chocolate chip one
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5x-2y ≤ 20 can you guys solve this.
Levart [38]

Your answer is y ≥ −10 + 5x/2
7 0
2 years ago
Read 2 more answers
Oh mah lord please please help me
Alenkinab [10]

Option 2: 4^{\frac{1}{6}} is the correct answer.

Step-by-step explanation:

The radical expressions like these are simplified by using fractional exponents

given

\frac{\sqrt{4}}{\sqrt[3]{4} }

Converting radicals into exponents

When there is no base the exponent is 1/2 and as the base is 3, the exponent will be 1/3

So

=\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}

As the bases of numerator and denominator is same, the exponents can be subtracted

=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}

Hence,

Option 2: 4^{\frac{1}{6}} is the correct answer.

Keywords: Exponents, radicals

Learn more about radicals at:

  • brainly.com/question/6073431
  • brainly.com/question/6075514

#LearnwithBrainly

7 0
3 years ago
A line that crosses segment at right angles while dividing the segment in half is called
iren [92.7K]

The correct answer is:

A line that crosses segment at right angles while dividing the segment in half is called <u>a perpendicular bisector</u>

Step-by-step explanation:

A bisector is a line that divides a line segment in two equal parts. A perpendicular bisector is a line that is perpendicular to given line segment and passes through the mid-point of the line segment. It can also be said as that the line perpendicular to a line segment that divides the lines in half is called the perpendicular bisector.

The correct answer is:

A line that crosses segment at right angles while dividing the segment in half is called <u>a perpendicular bisector</u>

Keywords: Perpendicular, bisector

Learn more about geometry at:

  • brainly.com/question/2115122
  • brainly.com/question/2116906

#LearnwithBrainly

8 0
2 years ago
What is the factorization of 729^15+1000​
Nesterboy [21]

\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) \\\\ a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} 729=27^2\\ \qquad (3^3)^2\\ 1000=10^3 \end{cases}\implies 729^{15}+1000\implies ((3^3)^2)^{15}+10^3 \\\\\\ ((3^2)^{15})^3+10^3\implies (3^{30})^3+10^3\implies (3^{30}+10)~~[(3^{30})^2-(3^{30})(10)+10^2] \\\\\\ (3^{30})^3+10^3\implies (3^{30}+10)~~~~[(3^{60})-(3^{30})(10)+10^2]

now, we could expand them, but there's no need, since it's just factoring.

3 0
3 years ago
Hi please help me the pic is up there
mojhsa [17]

Answer:

4p^3 (4p + 1)

Step-by-step explanation:

All we can do with this equation is factor it.

16p^4 + 4p^3  

When we look at the coefficients, there is a common factor of 4 with 16 and 4. The p's are also common factors, and we can take out a common factor of x^3. We can combine these common factors and take them out of the equation at the same time.

4p^3 (4p + 1)

8 0
2 years ago
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