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Tcecarenko [31]
3 years ago
9

Without drawing a graph find the intercepts of each line. y+5=–2x

Mathematics
1 answer:
Lostsunrise [7]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

The intercepts are where the line crosses the x and y axes.

To find the x- intercept ( where the line crosses the x- axis) let y = 0 in the equation and solve for x, that is

0 + 5 = - 2x

5 = - 2x ( divide both sides by - 2 )

x = - \frac{5}{2} = - 2.5 ← x- intercept ⇒ (- 2.5, 0 )

To find the y- intercept ( where the line crosses the y- axis ) let x = 0 in the equation and solve for y, that is

y + 5 = 0 ⇒ y = - 5 ← y- intercept ⇒ (0, - 5 )

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Solve the equation. Check for extraneous solutions. Type your answers in the blanks. Show your work. |4x+3| = 9+2x
GaryK [48]

Answer:

Step-by-step explanation:

|4x + 3| = 9 + 2x

We see the absolute value so we have to consider 2 cases:

(1)

4x + 3 = -9 - 2x

6x = -12

x = -2

(2)

4x + 3 = 9 + 2x

2x = 6

x = 3

Let's plug in both results.

|4(-2) + 3| = 9 + 2(-2)

|-5| = 9 - 4

5 = 5

Therefore x = -2 is a solution

|4(3) + 3| = 9 + 2(3)

|15| = 9 + 6

15 = 15

Therefore x = 3 is also a solution.

3 0
3 years ago
b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

The last box contained one-fourth the amount in the second box i.e.

⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

⇒ \frac{x}{2} +4x=63

⇒ \frac{9x}{2}=63

⇒ x=63(\frac{2}{9} )

⇒ x=14

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0
3 years ago
9/100 in simplest form?
shutvik [7]
9/100 is 9/100 in its simplest form.

You can also say that 9/100=0.09
6 0
3 years ago
Read 2 more answers
Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i
kolezko [41]

Answer:

Null hypothesis:\mu = 750  

Alternative hypothesis:\mu \neq 750  

t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943  

p_v =2*P(t_{4}>6.943)=0.00226  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.  

Step-by-step explanation:

Data given and notation

Data:    801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=811 represent the sample mean  

s=19.647 represent the standard deviation for the sample

n=5 sample size  

\mu_o =750 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:  

Null hypothesis:\mu = 750  

Alternative hypothesis:\mu \neq 750  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=5-1=4

What do you conclude?  

Compute the p-value  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{4}>6.943)=0.00226  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.  

4 0
3 years ago
Evaluate each expression by replacing the variable with 8. Show each step. (8 marks) 2n - 6
monitta

Answer:

10

Step-by-step explanation:

2n-6

n=8

2(8)-6

16-6

10

4 0
3 years ago
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