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Lesechka [4]
2 years ago
13

Find three consecutive even integers such that the sum of 5 and the second is multiplied by -7, the result is 11 greater than 5

times the opposite of the third
Mathematics
1 answer:
Rudiy272 years ago
8 0

Answer:

  -20, -18, -16

Step-by-step explanation:

For consecutive integer problems, it often works well to let a variable represent the middle one (or their average value).

__

Here, we can let x represent the second integer. Then the first is (x-2), and the third is (x+2). The given relation can be written as ...

  (5 +x)(-7) = 11 +5(-(x+2))

  -35 -7x = 11 -5x -10 . . . . . . eliminate parentheses

  -36 = 2x . . . . . . . . . add 7x -1

  -18 = x . . . . . . . . divide by 2

The three integers are -20, -18, -16.

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Step-by-step explanation:

For this exercise you need to remember the following formula:

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Where "V" is the speed, "d" is the distance and "t" is time.

In this case, according to the information given in the exercise, you know that:

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So, knowing those values, you can substitute them into the formula:

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Finally, evaluating, you get the following result:

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