Question

James decides to walk from school to the park tp play ball. The park is only 0.5 mile from the school. He leaves school at 3:15 and arrives at the park at 3:25. At what rate is james traveling

Answer 1

Answer: $0.05\ \frac{mi}{min}$

Step-by-step explanation:

For this exercise you need to remember the following formula:

$V=\frac{d}{t}$

Where "V" is the speed, "d" is the distance and "t" is time.

In this case, according to the information given in the exercise, you know that:

- James leaves his school at 3:15 and arrives at the park at 3:25. Then, you can identify that the time it takes him to go from his school to the park is:

$t=10\ min$

- The park is 0.5 miles from James' school. Therefore, you can identify that "d" is:

$d=0.5\ mi$

So, knowing those values, you can substitute them into the formula:

$V=\frac{0.5\ mi}{10\ min}$

Finally, evaluating, you get the following result:

$V=0.05\ \frac{mi}{min}$