(a) By the fundamental theorem of calculus,
<em>v(t)</em> = <em>v(0)</em> + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
The particle starts at rest, so <em>v(0)</em> = 0. Computing the integral gives
<em>v(t)</em> = [2/3 <em>u</em> ³ + 2<em>u</em> ²]₀ᵗ = 2/3 <em>t</em> ³ + 2<em>t</em> ²
(b) Use the FTC again, but this time you want the distance, which means you need to integrate the <u>speed</u> of the particle, i.e. the absolute value of <em>v(t)</em>. Fortunately, for <em>t</em> ≥ 0, we have <em>v(t)</em> ≥ 0 and |<em>v(t)</em> | = <em>v(t)</em>, so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of
∫₀⁸ <em>v(u)</em> d<em>u</em> = ∫₀⁸ (2/3 <em>u</em> ³ + 2<em>u</em> ²) d<em>u</em> = [1/6 <em>u</em> ⁴ + 2/3 <em>u</em> ³]₀⁸ = 1024
Answer:
8.875
Step-by-step explanation:
The +5 and -5 cancel, so you are left with -69=2-8g. Subtract two on both sides to get -71=-8g then divide both side by -8 to get g=8.875.
Answer:
- $38,500
- $1,400
Step-by-step explanation:
1. According to the Accrual Principle of Accounting, revenue should only recognized when the goods or services for which it was paid for have been delivered. In other words, revenue should only be recognized when earned.
As of December 1, 20X1, Ginzel had only completed 7 of the 20 reports so the revenue recognized should be for the completed reports alone.
Total revenue for 20 reports = $110,000
Revenue for 7 reports = 7/ 20 * 110,000
= $38,500
2. The Accrual principle also applies to expenses and states that expenses should only be accounted for when incurred. As the $4,000 relates to all the reports, it should be apportioned evenly.
The costs of extraction and conversion of data for the year should therefore be;
= 7/20 * 4,000
= $1,400
Answer:
The one you picked is right! Good job!
Answer:
31.4
Step-by-step explanation:
I reaally hope this helps you
