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2 years ago

You have 275 square inches of wrapping paper. Do you have enough wrapping paper to wrap the gift box shown?

Mathematics

1 answer:

Zigmanuir [339]2 years ago

8 0

The surface area of the box is bigger than the surface area of the available wrapping paper. Thus, you don't have enough wrapping paper to wrap the gift box.

The given parameters;

area of the wrapping paper available, A = 275 square inches
volume of the gift box, V = 343 in²

First, determine the length of each side of the box;

The length of each side is represented with x;

x³ = 343

$x = \sqrt[3]{343} \\\\x = 7 \ inches$

Second, find the surface area of the box;

surface area of the box, A = 6x²

A = 6(7)²

A = 294 in²

The surface area of the box is bigger than the surface area of the available wrapping paper. Thus, you don't have enough wrapping paper to wrap the gift box.

Learn more here: brainly.com/question/15908008

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Which shows solutions to X+4y=9 if X and y must be whole numbers? A. {(0,9)(1,5)(2,1)} B.{(2,1)(1,6)(0,9)} C.{(1,2)(5,1)(9,0) D.

Dafna11 [192]

The answer here is C. Let's proof.

Since we are dealing with whole numbers, select a constant for x to satisfy that y will result a whole number.
If x = 1, then the function would be 1 + 4y = 9. Solving for y,
4y = 9 - 1
4y = 8
y = 2
In ordered pair, that is (1,2)

Next, if x = 5, then 5 + 4y = 9. Solving for y,
4y = 9 - 5
4y = 4
y = 1
In ordered pair, that is (5,1).

Lastly, if x = 9, then 9 + 4y = 9. Solving for y,
4y = 9 - 9
y = 0/4
y = 0
In order pair, that is (9,0).

4 0

3 years ago

Read 2 more answers

Clevon forms a triangle with three straws measuring 20, 25, and 18 inches. To the nearest whole

Ne4ueva [31]

Answer:

Step-by-step explanation:

Let's label this triangle as triangle ABC. Side AB is 18, side BC is 20 and side CA is 25 and the angle we are looking for is angle C. Use the Law of Cosines to find the missing angle. You have to use the Law of Cosines because in order to use the Law of Sines you have to have an angle given and we don't so we have no other options. In our case,

$c^2=a^2+b^2-2abcosC$ which for us looks like this:

$18^2=20^2+25^2-2(20)(25)cosC$ and

$324=400+625-1000cosC$ and

$324=1025-1000cosC$ and

$-701=-1000cosC$ and

$.701=cosC$

Use the 2nd button and the cos button to find the missing angle.

Angle C = 45.4 which is, rounded to the nearest degree, 45°

8 0

3 years ago

marcy guessed the number of hershey kisses in the school jar. since she guessed correctly, she got to keep all of the candy. she

zaharov [31]

Answer:

118.............................

6 0

2 years ago

Aiden bought some noteboks and book covers for the upcoming school year.He bought a total of 13 items.Each notebook costs $1.37,

NARA [144]

Answer: Aiden bought 8 notebooks and 5 covers.

This is a system of equations problem. To solve this, we have to write 2 different equations and then solve them.

Our equations are:

x + y = 13
1.37x + 1.08y = 16.36

Where x is the number of notebooks and y is the number of covers.

To solve these equations, you can use anyone of these methods:
1) Graphing
2) Substitution
3) Elimination

The easiest way would be to graph them with a graphing calculator and find the point of intersection.

7 0

3 years ago

Toll Brothers is a luxury home builder that would like to test the hypothesis that the average size of new homes exceeds 2,400 s

boyakko [2]

Answer:

Since the pvalue of the test is 0.09 > 0.01, we do not reject the null hypothesis that the average size of new homes is of 2400 square feet.

Step-by-step explanation:

Toll Brothers is a luxury home builder that would like to test the hypothesis that the average size of new homes exceeds 2,400 square feet. Test to see if the average size of new homes exceeds 2,400 square feet.

At the null hypothesis, we test if the average is of 2400 square feet, that is:

$H_o: \mu = 2400$

At the alternate hypothesis, we test if the average is greater than 2400 square feet, that is:

$H_a: \mu > 2400$

The test statistic is:

Since we have the standard deviation for the sample, we use the t-distribution.

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

2400 is tested at the null hypothesis:

This means that $\mu = 2400$

A random sample of 36 newly constructed homes had an average of 2,510 square feet with a sample standard deviation of 480 square feet.

This means that $n = 36, X = 2510, s = 480$

Test statistic:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{2510 - 2400}{\frac{480}{\sqrt{36}}}$

$t = 1.375$

Pvalue of the test and decision:

The pvalue of the test is the probability of finding a sample mean of at least 2510, which is the pvalue of t = 1.375 with 36 - 1 = 35 degrees of freedom, using a one-tailed test.

With the help of a calculator, this pvalue is of 0.09

Since the pvalue of the test is 0.09 > 0.01, we do not reject the null hypothesis that the average size of new homes is of 2400 square feet.

6 0

2 years ago