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elena-14-01-66 [18.8K]
2 years ago
8

Evaluate the expression below at x = 5. x/35 + 5x^2

Mathematics
1 answer:
kramer2 years ago
4 0

Answer:

876/7

Step-by-step explanation:

Just plug the number 5 into the equation and solve. Remember your Order of Operations (PEMDAS).

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Owen earned $759 over the last 2 weeks. How much income tax will be withheld from his paycheck for this pay period? $ 2014 weekl
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That is a lot to do and work on
5 0
3 years ago
Solve for the missing angle ∡&. One point for your equation and one point for the correct angle measure.
love history [14]
Hello.

1. Understand that this requires inverse trigonometry.
2. For A, we can use sin^-1 if we want (we could use cos^-1 or tan^-1 as well because all sides are given)
Definition of sin^-1 with how it is derived
sin(theta) = O/H <—> sin^-1(O/H)
Angle A: (When calculating an angle, ensure that your calculation is in degree mode instead of radian mode.) 2ND, then QUIT on TI

sin^-1(7/25) = 16.26020471°
(round as needed)

Angle &: (also in degree mode)

All angles of a triangle add to 180°.
1. 180° - (angle B + Angle A) = Angle &
2. 180° - (90° + 16.26020471°) = 73.73979529°
(round as needed)

To quickly check: 16° + 90° + 73° = 180°, as expected for a triangle

From the picture you provided,

The angle values make sense because that triangle represents a 30-60-90 degree triangle. (Also, a good trick is to know that the smallest angle of a triangle will always have the smallest side value, and the largest angle has the largest side value.)
Unless we have an equilateral triangle!

Good luck to you!



8 0
3 years ago
The radius of the cone is 1.25 inches, and its height is 2.75 inches. If the diameter of the bubble gum ball is 0.5 inches, what
nasty-shy [4]
<h2>Explanation:</h2><h2></h2>

The volume of a cone can be found as:

V=\frac{1}{3}\pi r^2 h \\ \\ \\ Where: \\ \\ V:Volume \\ \\ r:radius \ of \ base \\ \\ h:height

Given the radius and height, we can find the volume of the cone:

V=\frac{1}{3}\pi r^2 h \\ \\ V=\frac{1}{3}\pi (1.25)^2(2.75) \\ \\ V=\frac{1}{3}\pi(1.5625)(2.75) \\ \\ V\approx 4.5in^3

The volume of a sphere is:

V=\frac{4}{3}\pi r^3 \\ \\ \text{Each gum ball has a diameter of 0.5in, so the radius is:} \\ \\ r=\frac{0.5}{2}=0.25in

So, for each gum ball the volume is:

V=\frac{4}{3}\pi r^3 \\ \\ V=\frac{4}{3}\pi (0.25)^3 \\ \\ V=0.065in^3

Therefore, the he closest approximation of the volume of the cone that can be filled with flavored ice is:

4.5-0.065=4.43in^3

Conclusion: The volume of the cone that can be filled with flavored ice is 4.43 cubic inches.

3 0
4 years ago
Find f(g(4)).<br> f(g(4)) =
Bas_tet [7]
F(g(4)) = fg(4) = 4fg
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4 years ago
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How many solutions does this system of equations have?
Crank

Answer:

2 solutions

Step-by-step explanation:

7 0
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