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Gekata [30.6K]
3 years ago
8

Can somebody help me

Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0
CAN I ALSO GET HELP ANYONE PLS?
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Would this problem be graphing, substitution, or elimination? A perfume maker has stocks of two perfumes on hand. Perfume A sell
Alex
Let a be the amt of perfume A, and b be the amt of perfume B. We have been given that

<span>a+b=3</span> and that <span>a∗15+b∗35=63</span>
From equation 1, we substitute <span>b=3−a</span> so as to get, <span>a∗15+(3−a)∗35=63

</span> which means, <span>15a+105−35a=63</span> which means, <span>−20a=−42

</span><span> so a = 2.1 ounce and b = 0.9 ounce</span>
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Answer: the answer is d

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