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Gekata [30.6K]
3 years ago
8

Can somebody help me

Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0
CAN I ALSO GET HELP ANYONE PLS?
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Yes please help me on this
otez555 [7]
15 abbabababababababababbababa
3 0
3 years ago
Identify all factors of the expression 12x^2-14x-6
Evgen [1.6K]

Let's solve this by using the quadratic formula:

\frac{-b+-\sqrt{b^2-4ac} }{2a}


Note that we only use the coefficients so a=12, b=-14, and c=-6.

Plug values in the quadratic equation:

\frac{ -  ( - 14)± \sqrt{ {( - 14)}^{2} - 4(12)( - 6) } }{2(12)}

And so by evaluating those values we obtain:

\frac{14+-\sqrt{484} }{24}=\frac{14+-22}{24}  \\\\

Now we have two answers which are our factors one where we add another where we subtract and so:

First factor:

\frac{14+22}{24}=\frac{36}{24}=\frac{3}{2}


Second Factor:

\frac{14-22}{24}=\frac{-8}{24}=-\frac{1}{3}


And so your factors are

\frac{3}{2},-\frac{1}{3}

meaning that those are your roots/x-intercepts.


6 0
3 years ago
Write "six times 3 minus 3" as an expression.
777dan777 [17]

Answer:

6(3)-3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Simplify: 8i^7+6i^5-5i^3-3i^2-7i-9
Dmitry_Shevchenko [17]
<span>Consider the remainder of the division of the power exponent of i by 4.
For a remainder r equal to 0, 1, 2 or 3, we have a power equal to 1, i, -1 or -i respectively, therefore:

</span>8i^7+6i^5-5i^3-3i^2-7i-9 =
8*(-i) + 6*i - 5*(-i) - 3*(-1) - 7i - 9 =
- 8i + 6i + 5i + 3 - 7i - 9 =
3 - 9 - 8i + 6i + 5i- 7i =
=\boxed{- 6 - 4i}

Answer:
\boxed{- 6 - 4i}

<span>

</span>
5 0
3 years ago
What is 1,334 divided by 23? A) 53 B) 56 C) 57 D) 58<br><br><br> The answer is D 58
Sindrei [870]
D is the answer?
Hope it helped!
5 0
4 years ago
Read 2 more answers
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