Answer:
∠XDQ : 41°
∠UXD: 139 °
Step-by-step explanation:
Allow me to rewrite your answer for a better understanding and please have a look at the attached photo.
<em>A segment XD is drawn in rectangle QUAD as shown below.
</em>
<em>What are the measures of ∠XDQ and ∠UXD ?
</em>
My answer:
As we can see in the photo, ∠ADX = 49° and ∠ADU =90°
=> ∠XDQ = ∠ADU - ∠ADX
= 90° - 49° = 41°
In the triangle ADX, we can find out the angle of ∠DXA
= 180° - ∠DAX - ∠ADX
= 180° - 90° - 49°
= 41°
=> <em>∠UXD = </em>180° - ∠DXA (Because UA is a straight line)
=180° - 41°
= 139 °
Answer:
you can approximate it to 61°
Answer:
A las 3 AM la temperatura era de -7 grados.
Step-by-step explanation:
Dado que la temperatura exterior era de 8 grados a la medianoche, y la temperatura bajó 5 grados durante cada una de las siguientes 3 horas, para determinar cuál era la temperatura a las 3 a.m. se debe realizar el siguiente cálculo:
8 - (3 x 5) = X
8 - 15 = X
-7 = X
Por lo tanto, a las 3 AM la temperatura era de -7 grados.
Answer:
(1) a+1/a=8a+2/8a+1
(2) a²-1/a²=(a+1)(a-1))a²
(8a+2)(8a)/(8a+1)²
I think your answer is D <span> slightly longer than one-half the length of the line segment</span>