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2 years ago

For a particular angle Θ, the cosine function f(x) = a cos b(Θ) has the following values within one cycle of the function:

Mathematics

1 answer:

expeople1 [14]2 years ago

7 0

If f(θ) = a cos(bθ), then from the first condition we find

f(0) = 3 ⇒ a cos(0) = 3 ⇒ a = 3

Together with the other conditions, it's evident that f(θ) has a period of π, so

2π/b = π ⇒ b = 2

so that

f(θ) = 3 cos(2θ)

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Can someone please help me with this :(

konstantin123 [22]

Answer:

(it will take super long for me to answer this)

Step-by-step explanation:

Use desmos graphing calculator, put in your f(x)/y values and you will get all of the answers you need. Hope this is helpful :)

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3 years ago

Pls help I need a good grade

aleksley [76]

Answer:

f= -14

Step-by-step explanation:

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3 years ago

Read 2 more answers

of the last 15 contestants on a game show, 3 won a prize. Considering this data, how many of the next 20 contestants would you e

nadya68 [22]

You do 3/15 which is 0.2

then 0.2*20 which is 4

you can expect 4 to win a prize

hope this helps and you rate me good;)

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3 years ago

school teacher and needs 22 pieces of wood, 3 over 8 ft long, for a class project. If he has a 9-ft board from which to cut the

tiny-mole [99]

Answer:

Yes, he will have enough 3 over 8 ft pieces for his class.

Step-by-step explanation:

Given:

Number of wood required = 22

Length of each wood, $l=\frac{3}{8}\textrm{ ft}$

Total length of the board, $L=9\textrm{ ft}$

Therefore, the number of woods that can be made using the given board is given as:

$\textrm{Number of woods made}=\frac{\textrm{Total length of board}}{\textrm{Length of each wood}}\\\textrm{Number of woods made}=\frac{L}{l}=\frac{9}{\frac{3}{8}}=9\times \frac{8}{3}=\frac{72}{3}=24$

So, he can make 24 woods of length $\frac{3}{8}\textrm{ ft}$ using the 9 ft board. But he has to make only 22 pieces.

Therefore, he has enough of the wood to make the required number of pieces.

3 0

3 years ago

An object is launched straight up into

DiKsa [7]

Answer:

t ∈ {1, 3}

Step-by-step explanation:

You want to find t such that ...

h = 27

27 = -8t^2 +32t +3 . . . . . . substitute the expression for h

24 = -8t^2 +32t . . . . . . . . . subtract 3

-3 = t^2 -4t . . . . . . . . . . . . . divide by -8

1 = t^2 -4t +4 = (t -2)^2 . . . . add 4 to complete the square

±√1 = t -2 . . . . . . . . . . . . . . take the square root

t = 2 ± 1 . . . . . . . . . . . . . . . . add 2

t = 1 or 3

The object is 27 ft off the ground at t = 1 and again at t = 3.

8 0

3 years ago