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kari74 [83]
2 years ago
11

For a particular angle Θ, the cosine function f(x) = a cos b(Θ) has the following values within one cycle of the function:

Mathematics
1 answer:
expeople1 [14]2 years ago
7 0

If f(θ) = a cos(bθ), then from the first condition we find

f(0) = 3   ⇒   a cos(0) = 3   ⇒   a = 3

Together with the other conditions, it's evident that f(θ) has a period of π, so

2π/b = π   ⇒   b = 2

so that

f(θ) = 3 cos(2θ)

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