An object is launched straight up into
1 answer:
Answer:
t ∈ {1, 3}
Step-by-step explanation:
You want to find t such that ...
h = 27
27 = -8t^2 +32t +3 . . . . . . substitute the expression for h
24 = -8t^2 +32t . . . . . . . . . subtract 3
-3 = t^2 -4t . . . . . . . . . . . . . divide by -8
1 = t^2 -4t +4 = (t -2)^2 . . . . add 4 to complete the square
±√1 = t -2 . . . . . . . . . . . . . . take the square root
t = 2 ± 1 . . . . . . . . . . . . . . . . add 2
t = 1 or 3
The object is 27 ft off the ground at t = 1 and again at t = 3.
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Answer:
If we assume that everyone in the group is an owner, we would have
legs.
legs
Therefore, we need 24 more legs.
These 24 additional legs can be made from the difference of legs between the owners and dogs.
In this case, dogs have more legs than an owner.
24 ÷ 2 = 12.
There are 12 dogs in the group.