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zubka84 [21]
2 years ago
12

João claims he can read minds. His friend Pedro asked him to guess a number he was thinking of between 1 and 7 (inclusive). João

guessed Pedro's number correctly 4 out of 9 times.
Let's test the hypothesis that João cannot read minds and therefore has a chance of
1/7 of guessing the correct number each time versus the alternative that his chance is somehow greater.
The table below sums up the results of 1000 simulations, each simulating 9 guesses with a chance of 1/7 start fraction, 1, divided by, 7, end fraction of being correct.
According to the simulations, what is the probability of having 4 or more correct guesses out of ?




Let's agree that if the observed outcome has a probability less than 1\%1%1, percent under the tested hypothesis, we will reject the hypothesis.
What should we conclude regarding the hypothesis?
Choose 1 answer:
Choose 1 answer:

(Choice A)

We cannot reject the hypothesis.

(Choice B)

We should reject the hypothesis.

correct guesses out of 9 Frequency
0 250
1 375
2 250
3 97
4 24
5 4
6 0
7 0
8 0
9 0
Mathematics
1 answer:
Ksju [112]2 years ago
5 0

It can be deduced that the probability of having 4 or more correct guesses will be 0.0296.

<h3>How to calculate the probability</h3>

From the given information, the null hypothesis is p = 1/7 and the alternate hypothesis is p>1/7. In this case, the mind reader gets a 4 out of 9 chances.

In order to test the hypothesis, simulations for 10000 cases were run with a probability of the correct answer being 1/7.

In this case, the p-value is the probability of correct answers that are greater than 4, assuming the null hypothesis is true. Here the p-value is 0.0296.

Also, the significance level to reject the hypothesis is less than 0.01. Since p > 0.01, we then fail to reject the hypothesis. Therefore the null hypothesis stands and Joao is not a mind reader.

Learn more about probability on:

brainly.com/question/24756209

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Question has missing details (Full question below)

Measurement error that is continuous and uniformly distributed from –3 to +3 millivolts is added to a circuit’s true voltage. Then the measurement is rounded to the nearest millivolt so that it becomes discrete. Suppose that the true voltage is 219 millivolts. What is the mean and variance of the measured voltage

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Step-by-step explanation:

Given

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