Question

A circuit has a current of 1.2 a. if the voltage decreases to one-third of its original amount while the resistance remains constant, what will be the resulting current? 0.3 a 0.4 a 1.2 a 3.6 a

Answer 1

Given that the resistance remains constant, if the voltage decreases to one-third of its original amount, the resulting current in the circuit is 0.4A

What is Ohm's Law?

Ohm’s law states that the potential difference between two points is directly proportional to the current flowing through the resistance.

It is expressed as;

V = IR

Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.

Given that;

Initially, A circuit has a current I = 1.2A

V = IR

R = V/I

R = V/1.2A ...... let this be equation 1

Next, voltage decreases to one-third of its original amount while the resistance remains constant.

Meaning Voltage = 1/3 of V = V/3

Hence;

V = IR

V/3 = IR

From equation 1 ( R = V/1.2A )

V/3 = I × V/1.2A

V/3 = IV/1.2A

We cross multiply

V1.2A = 3IV

I = V1.2A / 3V

I = 1.2A / 3

I = 0.4A

Therefore, given that the resistance remains constant, if the voltage decreases to one-third of its original amount, the resulting current in the circuit is 0.4A

Learn more about potential difference here: brainly.com/question/2364325

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Answer 2

Answer:

0.4 A

Step-by-step explanation:

When resistance is constant, current is proportional to voltage. When 1/3 the voltage is applied, 1/3 the current will result. (1/3)* (1.2 A) = 0.4 A The resulting current will be 0.4 A.