Answer:
Yes
Step-by-step explanation:
When we solve it we get 0.5 which is 1/2 in fraction from
Answer:
Step-by-step explanation:
Emma is making two different kinds of cookies for a cookie party she will be attending. She needs 2 and 2/3 cups of sugar for the first recipe and 1 and 1/4 cups of sugar for the second recipe. Emma thinks she will have enough sugar but she isn't quite sure. She knows that her full 2 pound bag of sugar says it contains 4 and 1/2 cups of sugar. Determine the exact difference between the amount of sugar Emma has and the amount of sugar she needs for the recipes.) Emma's mom brought home another 2 pound bag of sugar (4 and 1/2 cups) and wants to make fudge to take to work. Her mom will need 2 and 1/6 cups of sugar. Write a numerical expression that could be used to determine exactly how much sugar will be left over from the two bags of sugar after Emma bakes cookies and her mom makes fudge
First you want to write 7x as a sum or difference: 15x-8x
Now, the expression would look like this: 10x^2+15x-8x-12
Next, factor out the 5x and -4 from the expression: 5x(2x+3)-4(2x+3)
Now, factor out the 2x+3 from the expression and you have your answer:
(2x+3)(5x-4)
Answer:
Rational
Step-by-step explanation:
It can be expressed as the ratio of two integers.
i.e. 0.01011011101111 = 1 011 011 101 111 / 100 000 000 000 000
![\quad \huge \quad \quad \boxed{ \tt \:Answer }](https://tex.z-dn.net/?f=%5Cquad%20%5Chuge%20%5Cquad%20%5Cquad%20%5Cboxed%7B%20%5Ctt%20%5C%3AAnswer%20%7D)
![\qquad \tt \rightarrow \:m\overbrace{DB}= 90 \degree](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3Am%5Coverbrace%7BDB%7D%3D%2090%20%5Cdegree)
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![\large \tt Solution \: :](https://tex.z-dn.net/?f=%20%5Clarge%20%5Ctt%20Solution%20%20%5C%3A%20%3A%20)
![\qquad \tt \rightarrow \: m \overbrace{DB} + m \overbrace{TB} = 180 \degree](https://tex.z-dn.net/?f=%20%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3A%20m%20%5Coverbrace%7BDB%7D%20%20%2B%20m%20%5Coverbrace%7BTB%7D%20%20%3D%20180%20%5Cdegree)
[ linear pair ]
![\qquad \tt \rightarrow \: m \overbrace{DB} + 90 \degree = 180 \degree](https://tex.z-dn.net/?f=%20%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3A%20m%20%5Coverbrace%7BDB%7D%20%20%2B%2090%20%5Cdegree%20%20%3D%20180%20%5Cdegree)
![\qquad \tt \rightarrow \: m \overbrace{DB} = 180 \degree - 90 \degree](https://tex.z-dn.net/?f=%20%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3A%20m%20%5Coverbrace%7BDB%7D%20%20%20%20%3D%20%20180%20%5Cdegree%20%20%20%20-%2090%20%5Cdegree)
![\qquad \tt \rightarrow \: m \overbrace{DB} = 90 \degree](https://tex.z-dn.net/?f=%20%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3A%20m%20%5Coverbrace%7BDB%7D%20%20%20%20%3D%20%20%2090%20%5Cdegree)
Answered by : ❝ AǫᴜᴀWɪᴢ ❞