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Thepotemich [5.8K]
3 years ago
10

Find the probability of throwing 9 with two dice.

Mathematics
1 answer:
ololo11 [35]3 years ago
6 0
Total number of possible outcomes of throwing two dice = 6×6 = 36
Number of outcomes of getting 9 i.e, (3+6),(4+5),(5+4),(6+3) = 4

P = \frac{Number \: of \: favourable \: outcomes}{ Total \: number \: of \: possible \: outcomes}

P (throwing \: 9) = \frac{4}{36} = \frac{1}{9}
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Step-by-step explanation:

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3 years ago
Given: x - 6.3333 ≤ 1.5 .
Inessa05 [86]

Answer:

x or (-\infty, 47/6]

Step-by-step explanation:

Note that 6.3333 = 6 1/3 = 19/3 = 38/6.

Also, note that 1.5 = 1 1/2 = 3/2 = 9/6.

So, the inequality is really equal to x-38/6.

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So, the solution is x, or in interval notation, (-\infty, 47/6]

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2 years ago
A supervisor records the repair cost for 14 randomly selected refrigerators. A sample mean of $79.20 and standard deviation of $
Nitella [24]

Answer:

( $74.623, $83.777)

The 90% confidence interval is = ( $74.623, $83.777)

Critical value at 90% confidence = 1.645

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = $79.20

Standard deviation r = $10.41

Number of samples n = 14

Confidence interval = 90%

Using the z table;

The critical value that should be used in constructing the confidence interval.

z(α=0.05) = 1.645

Critical value at 90% confidence z = 1.645

Substituting the values we have;

$79.20+/-1.645($10.42/√14)

$79.20+/-1.645($2.782189528308)

$79.20+/-$4.576701774067

$79.20+/-$4.577

( $74.623, $83.777)

The 90% confidence interval is = ( $74.623, $83.777)

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8.234 E14 in standard form
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Answer:

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Step-by-step explanation:

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Write the augmented matrix for the given system. x + 3y + 5z = -3 -5y + 3z = -8 -8z = -6
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\begin{pmatrix} 1  & 3 &  5 & | &  -3& \\ 0 & 5 & 3 & | &  -8 \\  0 & 0 & -8 & | & -6 \end{pmatrix}

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3 years ago
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