Answer:
∫₂³ √(1 + 64y²) dy
Step-by-step explanation:
∫ₐᵇ f(y) dy is an integral with respect to y, so the limits of integration are going to be the y coordinates. a = 2 and b = 3.
Arc length ds is:
ds = √(1 + (dy/dx)²) dx
ds = √(1 + (dx/dy)²) dy
Since we want the integral to be in terms of dy, we need to use the second one.
ds = √(1 + (8y)²) dy
ds = √(1 + 64y²) dy
Therefore, the arc length is:
∫₂³ √(1 + 64y²) dy
<span>Using
the points (2, 45) (4, 143) and (10, 869), we can plug them into the
following system of 3 equations using the y = ax^2 + bx + c format:
45 = a(2)^2 + b(2) + c
143 = a(4)^2 + b(4) + c
869 = a(10)^2 + b(10) + c
which simplifies to:
45 = 4a + 2b + c
143 = 16a + 4b + c
869 = 100a + 10b + c
Solving the system, we get a = 9, b = -5, and c = 19. Thus the equation is:
c(x) = 9x^2 - 5x + 19
If you have a TI graphing calculator, you can also enter the points by
pressing Stat -> Edit and enter (2, 45) (4, 143) and (10, 869) into
it. Go back and calculate the QuadReg of the points from the Calc tab
and it will give you the same answer.
Now that we know the function that will produce the price of production
for any number of calculators, plug in x = 7 and it will give you the
price to produce 7 calculators.
c(x) = 9x^2 - 5x + 19
==> c(7) = 9(7)^2 - 5(7) + 19
==> c(7) = 441 - 35 + 19
==> c(7) = 425
Therefore, it costs $425 to produce 7 calculators.
Hope this helps.
</span>
If you meant y = 27x - 3, OK. Then, if x = 4, y = 27(4) - 3, or 108-3 = 105.
Hello!
I have all the work but I do not know how to post it on here.
The area of the figure shown is 57.
I hope it helps!
