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Thepotemich [5.8K]
3 years ago
10

Find the probability of throwing 9 with two dice.

Mathematics
1 answer:
ololo11 [35]3 years ago
6 0
Total number of possible outcomes of throwing two dice = 6×6 = 36
Number of outcomes of getting 9 i.e, (3+6),(4+5),(5+4),(6+3) = 4

P = \frac{Number \: of \: favourable \: outcomes}{ Total \: number \: of \: possible \: outcomes}

P (throwing \: 9) = \frac{4}{36} = \frac{1}{9}
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Step-by-step explanation:

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The sum of the digits of a 2-digit number is 10. If 18 is added to the number, the digits of the new number are those of the ori
Aliun [14]

Answer:

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Step-by-step explanation:

Let (ab) represent a number with a in the ten's position and b is the one's position.

This means (ab) actually has value of 10a+b.

We are given the sum of those digits of (ab) is 10; this means a+b=10.

It says if 18 is added to the number (ab), then the result is (ba).

So (ab) has value 10a+b and

(ba) has value 10b+a.

We are given then:

(ab)+18=(ba)

10a+b+18=10b+a

Subtract 10a on both sides:

b+18=10b+a-10a

Simplify:

b+18=10b-9a

Subtract b on both sides:

18=10b-b-9a

18=9b-9a

Divide both sides by 9:

2=b-a

Rearrange by commutative property:

2=-a+b

So the system of equations we want to solve is:

a+b=10

-a+b=2

-------------------------Add equations together (this will eliminate the variable a and allow you to go ahead and solve for b:

0+2b=12

2b=12

Divide both sides by 2:

b=\frac{12}{2}

Simplify:

b=6

If b=6 and a+b=10, then a=4.  a=4 since 4+6=10.

So the original number is (46).

18 more than 46 is 18+46=(64) which is what we wanted.

We also have the sum of 4 and 6 is 10 as well.

7 0
3 years ago
513 as a percentage of 900
zavuch27 [327]
513 as a percentage of 900 can be re-written as;
\frac{513}{900} *100
= 57 percent
5 0
3 years ago
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