Question

Find the probability of throwing 9 with two dice.

Answer 1

Total number of possible outcomes of throwing two dice = 6×6 = 36
Number of outcomes of getting 9 i.e, (3+6),(4+5),(5+4),(6+3) = 4

$P = \frac{Number \: of \: favourable \: outcomes}{ Total \: number \: of \: possible \: outcomes}$

$P (throwing \: 9) = \frac{4}{36} = \frac{1}{9}$