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Studentka2010 [4]
2 years ago
14

Find the value of 11 +22+33 + ... + 1100.

Mathematics
1 answer:
ella [17]2 years ago
5 0

Answer:

sum of terms: 55550

Explanation:

\sf S_n = \dfrac{n}{2} (u_{start}+u_{end}})

Here the number of terms:

1100 ÷ 11 = 100

Using the Formula:

\sf \dfrac{100}{2} (11+1100)

\sf 55550

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Expanded notation for 55,032178
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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). The vertex of a
dolphi86 [110]
Vertex form:
y-k=a(x-h)^2
h=-2,k=-20,y=-12 when x=0
thus;
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Equation:
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3 years ago
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In the figure, PQ is parallel to RS. The length of RP is 2 cm; the length of PT is 18 cm; the length of QT is 27 cm. What is the
Sidana [21]

Step 1    

<u>Find the value of TS</u>

we know that

if PQ is parallel to RS. then triangles TRS and TPQ are similar

so

\frac{TR}{TP} =\frac{TS}{QT}

solve for TS

TS =\frac{TR*QT}{TP}

we have

RP=2\ cm\\TP=18\ cm\\QT=27\ cm

TR=TP+RP\\TR=18+2=20\ cm

substitute

TS =\frac{20*27}{18}  

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Step 2

<u>Find the value of SQ</u>

we know that

SQ=TS-QT

we have

TS =30\ cm

QT=27\ cm

substitute

SQ=30\ cm-27\ cm=3\ cm

therefore

<u>the answer is</u>

the value of SQ is 3\ cm

6 0
3 years ago
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I’m confused on this one
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The awnser is 864 just multiply them together
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e-lub [12.9K]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
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