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Studentka2010 [4]
1 year ago
14

Find the value of 11 +22+33 + ... + 1100.

Mathematics
1 answer:
ella [17]1 year ago
5 0

Answer:

sum of terms: 55550

Explanation:

\sf S_n = \dfrac{n}{2} (u_{start}+u_{end}})

Here the number of terms:

1100 ÷ 11 = 100

Using the Formula:

\sf \dfrac{100}{2} (11+1100)

\sf 55550

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ratelena [41]

Answer:

f/6=17

f=17×6

=102

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2 years ago
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Help meeeeeeeee answer these questions or correct them your like my human checker because calculators to check get boring
IRISSAK [1]
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3 years ago
Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.
Leviafan [203]

Answer:

Option D. 3.73​

Step-by-step explanation:

we know that

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

and

sin^{2}(\alpha)+cos^{2}(\alpha)=1

step 1

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we have

sin(x)=\frac{1}{2}

we know that

sin^{2}(x)+cos^{2}(x)=1

substitute

(\frac{1}{2})^{2}+cos^{2}(x)=1

cos^{2}(x)=1-\frac{1}{4}

cos^{2}(x)=\frac{3}{4}

cos(x)=\frac{\sqrt{3}}{2}

step 2

Find tan(x)

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substitute

tan(x)=1/\sqrt{3}

step 3

Find sin(y)

we have

cos(y)=\frac{\sqrt{2}}{2}

we know that

sin^{2}(y)+cos^{2}(y)=1

substitute

sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1

sin^{2}(y)=1-\frac{2}{4}

sin^{2}(y)=\frac{2}{4}

sin(y)=\frac{\sqrt{2}}{2}

step 4

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substitute

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step 5      

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tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

substitute

tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73

7 0
3 years ago
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Answer:

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