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Xelga [282]
3 years ago
9

1/10 of 800 is ten times as much as __________

Mathematics
2 answers:
Fittoniya [83]3 years ago
6 0

Answer:

8

Step-by-step explanation:

1/8 of 800 is 80 . ten times 8 is 800

kondaur [170]3 years ago
4 0

Answer:

8

Step-by-step explanation:

1/10 of 800 is 80. Ten times 8 is 80

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There were 28 white ducks swimming in a pond.
pickupchik [31]
28 white ducks swimming in pond
2*(28 white ducks) = 56 brown ducks flew and landed in pond
(28 white ducks)/2 = 14 white ducks remained in the pond

Ducks remaining in the pond (at this point):
(14 white ducks) + (56 brown ducks) = <u><em>70 ducks in all</em></u>
8 0
3 years ago
The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
3 years ago
Mary walks the 3 day breast cancer walk. They break the 62 miles evenly for each day. How
Semmy [17]

Answer:

she would walk at least those 62 miles

Step-by-step explanation:

We are told that in the 3 days of the walk to fight cancer, Mary breaks the 62 mile barrier every day, that is to say that every day she travels 62 miles or more.

You ask us how much she walks in a single day, considering what the statement that goes at least 62 miles each day says, she would walk at least those 62 miles on a normal day.

4 0
3 years ago
I need help with this please help :)
Tanya [424]
ANSWER : it is a right angle
6 0
3 years ago
Read 2 more answers
What is the midpoint of the line segment with endpoints at (12,7)and (18,19)
Mrac [35]

Answer:

(15, 13)

Step-by-step explanation:

Midpoint is the half of the segment.

What I did to solve this was adding the two xs together to get 30 then find the average of 30 by dividing it by 2. This would give you 15

I did the same thing with the ys and got 13

hope this made sense

6 0
3 years ago
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