Question

Four types of soda are served at a birthday party. in an icebox containing a large number of cans of soda, 20% are ambrase, 30% are butonic, 15% are colana, and 35% are dynamite. a party guest randomly chooses four cans of soda. calculate the probability that the guest chooses one of each type of soda.

Answer 1

The probability that the guest chooses one of each type of soda will be 8.03%.

What is probability?

Its simple notion is that something will most likely occur. The favorable event's proportion to the overall number of occurrences.

Four types of soda are served at a birthday party. in an icebox containing a large number of cans of soda, 20% are Ambrase, 30% are Butonic, 15% are Colana, and 35% are Dynamite.

A party guest randomly chooses four cans of soda.

Then the probability that the guest chooses one of each type of soda will be

Let the total number of the soda can will be 100. Then we have

Ambrase = 20

Butonic = 30

Colana = 15

Dynamite = 35

$\rm P = \dfrac{^{20}C_1 \times ^{30}C_1\times ^{15}C_1\times ^{35}C_1}{^{100}C_4}\\\\\\P =\dfrac{20 \times 30 \times 15 \times 35}{3921225}\\\\\\P = \dfrac{600}{7469}\\\\\\P = 0.08033\\\\\\P = 8.03\%$

More about the probability link is given below.

brainly.com/question/795909

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