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3 years ago

If y varies directly as x, and y is 12 when x is 1.2, what is the constant of variation for this relation?

Mathematics

2 answers:

laila [671]3 years ago

6 0

If you multiply 12 by 0.1, you get 1.2. To write this as a function you would say y is x multiplied by 0.1.
y=0.1x

Andrej [43]3 years ago

5 0

Answer:

B. 10

Step-by-step explanation:

y = k x

12 = k 1.2

k = 12/1.2

k = 10

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In order to solve the following system of equations by addition, which of the

Pavlova-9 [17]

Answer:

Multiply the top equation by -3 and the bottom equation by 2

Step-by-step explanation:

Given system of equations:

$\begin{cases}4x-2y=7\\3x-3y=15 \end{cases}$

To solve the given system of equations by addition, make one of the variables in both equations sum to zero. To do this, the chosen variable must have the same coefficient, but it should be negative in one equation and positive in the other, so that when the two equations are added together, the variable is eliminated.

To eliminate the variable y:

Multiply the top equation by -3 to make the coefficient of the y variable 6:

$\implies -3(4x-2y=7) \implies -12x+6y=-21$

Multiply the bottom equation by 2 to make the coefficient of the y variable -6:

$\implies 2(3x-3y=15) \implies 6x-6y=30$

Add the two equations together to eliminate y:

$\begin{array}{l r r}& -12x+6y= &-21\\+ & 6x-6y= & 30\\\cline{1-3}& -6x\phantom{))))))} = & 9\end{array}$

Solve for x:

$\implies -6x=9$

$\implies x=-\dfrac{9}{6}=-\dfrac{3}{2}$

Substitute the found value of x into one of the equations and solve for y:

$\implies 3\left(-\dfrac{3}{2}\right)-3y=15$

$\implies -\dfrac{9}{2}-3y=15$

$\implies -3y=\dfrac{39}{2}$

$\implies y=-\dfrac{39}{2 \cdot 3}$

$\implies y=-\dfrac{13}{2}$

Learn more about systems of equations here:

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What is the volume in the tank after two hours of the pumps running v(t)= 65t + 280

alina1380 [7]

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erica [24]

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